Note: This program will work only with Internet Explorer.
In this article I will explain how to insert records to a database using TextBox in JavaScript.
First I created a database EmpDetail. Then I created a table in this database.
Query Code
CREATE TABLE [dbo].[Emp_Info](
[Emp_Id] [int] NULL,
[Name] [varchar](50) NULL,
[Salary] [int] NULL,
[City] [varchar](50) NULL
) ON [PRIMARY]
Now insert some data into the Emp_Info table. Then use the following procedure.
Complete Program
Insert_Value.htm
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script type="text/javascript" >
function InsertRecord()
{
var txtid = document.getElementById('txtid').value;
var txtname = document.getElementById('txtname').value;
var txtsalary = document.getElementById('txtsalary').value;
var txtcity = document.getElementById('txtcity').value;
if (txtid.length != 0 || txtname.length !=0 || txtsalary.length !=0|| txtcity.length !=0)
{
var connection = new ActiveXObject("ADODB.Connection");
var connectionstring = "Data Source=.;Initial Catalog=EmpDetail;Persist Security Info=True;User ID=sa;Password=****;Provider=SQLOLEDB";
connection.Open(connectionstring);
var rs = new ActiveXObject("ADODB.Recordset");
rs.Open("insert into Emp_Info values('" + txtid + "','" + txtname + "','" + txtsalary + "','" + txtcity + "')", connection);
alert("Insert Record Successfuly");
txtid.value = " ";
connection.close();
}
else
{
alert("Please Enter Employee \n Id \n Name \n Salary \n City ");
}
}
function ShowAll()
{
var connection = new ActiveXObject("ADODB.Connection");
var connectionstring = "Data Source=.;Initial Catalog=EmpDetail;Persist Security Info=True;User ID=sa;Password=****;Provider=SQLOLEDB";
connection.Open(connectionstring);
var rs = new ActiveXObject("ADODB.Recordset");
rs.Open("select * from Emp_Info ", connection);
rs.MoveFirst();
var span = document.createElement("span");
span.style.color = "Blue";
span.innerText = " ID " + " Name " + " Salary" + " City ";
document.body.appendChild(span);
while (!rs.eof)
{
var span = document.createElement("span");
span.style.color = "green";
span.innerText = "\n " + rs.fields(0) + " | " + rs.fields(1) + " | " + rs.fields(2) + " | " + rs.fields(3);
document.body.appendChild(span);
rs.MoveNext();
}
rs.close();
connection.close();
}
</script>
<style type="text/css">
#main
{
height: 264px;
}
#ShowRecord
{
width: 67px;
z-index: 1;
left: 20px;
top: 257px;
position: absolute;
}
#showall
{
z-index: 1;
left: 114px;
top: 257px;
position: absolute;
}
</style>
</head>
<body style="height: 431px">
<div id="show"
style="font-size: x-large; font-weight: bold; height: 298px; color: #009999;">
Insert Employee Record<p style="font-size: medium; color: #000000;">
Employee Id
<input id="txtid" type="text" /></p>
<p style="font-size: medium; color: #000000;">
Name
<input id="txtname" type="text" /></p>
<p style="font-size: medium; color: #000000;">
Salary
<input id="txtsalary" type="text" /></p>
<p style="font-size: medium; color: #000000;">
City
<input id="txtcity" type="text" /></p>
<input id="ShowRecord" type="button" value="Insert" onclick="InsertRecord()" />
<input id="showall" type="button" value="Show All Record" onclick="ShowAll()" /></div>
</body>
</html>
Output 1
Click on the "Show All Record" button.
![]()
![click-on-show.jpg]()
Output 2
Insert records in the textboxes then click on the "Insert" button.
![insert-record.jpg]()
Output 3
After inserting a record, click on the "Show All Record" button. You will see the record inserted successfully.
![insert-record.jpg]()
Output 4
If you click on the Insert button without entering any value in the textboxes then it will show the error.
![error.jpg]()
For more information, download the attached sample application.