Alphabet Pattern 'I' in Python

Code:

str="";
for Row in range(0,7):
    for Col in range(0,7):
        if (Col == 3 or (Row == 0 and Col > 0 and Col < 6) or (Row == 6 and Col > 0 and Col < 6)):
            str=str+"*"
        else:
            str=str+" "
    str=str+"\n"
print(str);

Output: