Alphabet Pattern 'I' in Python
In this Blog I am printing pattern 'I' using Python
Code:
- str="";
- for Row in range(0,7):
- for Col in range(0,7):
- if (Col == 3 or (Row == 0 and Col > 0 and Col < 6) or (Row == 6 and Col > 0 and Col < 6)):
- str=str+"*"
- else:
- str=str+" "
- str=str+"\n"
- print(str);
Output: