Alphabet Pattern 'S' in Python

S-Pattern 1: 

Code:

str="";
for Row in range(0,7):
    for Col in range(0,7):
        if (((Row == 0 or Row == 3 or Row == 6) and Col > 1 and Col < 5) or (Col == 1 and (Row == 1 or Row == 2 or Row == 6)) or (Col == 5 and (Row == 0 or Row == 4 or Row == 5))):
            str=str+"*"
        else:
            str=str+" "
    str=str+"\n"
print(str);

Output: 

 

 

S-Pattern 1:

Code:

row=15
col=18
str=""
for i in range(1,row+1):
    if((i<=3)or(i>=7 and i<=9)or(i>=13 and i<=15)):
        for j in range(1,col):
            str=str+"*"
        str=str+"\n"
    elif(i>=4 and i<=6):
        for j in range(1,5):
            str=str+"*"
        str=str+"\n"
    else:
        for j in range(1,14):
            str=str+" "
        for j in range(1,5):
            str=str+"*"
        str=str+"\n"
print(str)

Output: