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Answers

A pointer converted into A pointer to a pointer in c++

Ken H

Ken H

9y
660
1
 Hi friend,
  
    Here is an about:A pointer converted into A pointer to a pointer question. 
 
Please See my code below(Font in bold): 
 
#include "stdafx.h"
#include <windows.h>
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[]){  
     int x;
int *p;
int **q;
x = 100;
cout << "Address field of &x(own)=" << &x << endl;
cout << "Value field of x=" << x << endl;
p = &x;
cout << "\nAddress field of &p(own)=" << &p << endl;
cout << "Value field of p=" << p << endl;
cout << "Value field of *p=" << *p << endl;
q=&p;
cout << "\nAddress field of &q(own)=" << &q << endl;
cout << "Value field of q=" << q << endl; // Value field holds the address of the p.
cout << "Value field of *q=" << *q << endl;
cout << "Value field of **q=" << **q << endl;
int *p2 = *q;
cout << "\nAddress field of &p2(own)=" << &p2 << endl;
cout << "Value field of p2=" << p2 << endl;
cout << "Value field of *p2=" << *p2 << endl;
q = (int**)p;
cout << "\nAddress field of &q(own)=" << &q << endl;
cout << "Value field of q=" << q << endl;
cout << "Value field of *q=" << *q << endl; // Print result is Hex(decimal:100 -> hex:00000064). Why is not output the decimal 100?
cout << "Value field of (int)*q=" << (int)*q << endl; // Converted to decimal.  
system("pause");
return 0;
 
 
Thank.
 
 
 
 
Answers (2)