About Regular Expressions using Groups

Question

Hello All I want to break the string by using the Regular Expression: String:((ALLRAD + !(812_ENGLAND US)) or ( ((ALLRAD + !(812_ENGLAND US))) or (( ((ALLRAD + !(812_ENGLAND US)))) Output:(ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) Thanks in Advance

Vulpes · Answer

This is just a generalization of the expression in your previous thread: http://www.c-sharpcorner.com/forums/thread/252590/about-regular-expressions.aspx The following should deal with any number of brackets at either end of the text: using System; using System.Text.RegularExpressions; class Test { static void Main() { string[] strs = { ALLRAD + !(812_ENGLAND US) (ALLRAD + !(812_ENGLAND US) ((ALLRAD + !(812_ENGLAND US)) (((ALLRAD + !(812_ENGLAND US))) ((((ALLRAD + !(812_ENGLAND US)))) }; string regExp = @^$*(\w+\s*\+\s*(!)?)\((\w+(\s*\w+)*)$*$; for(int i = 0; i { Match m = Regex.Match(strs[i] regExp); string[] split = Regex.Split(m.Groups[3].Value @\s*); string[] output = new string[split.Length]; for(int j = 0; j { output[j] = String.Format(({0}({1})) m.Groups[1] split[j]); Console.WriteLine(output[j]); } Console.WriteLine(); } Console.ReadKey(); } } The output is: (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US)) (ALLRAD + !(812_ENGLAND)) (ALLRAD + !(US))