array of objects : NullReferenceException

Question

Greetings could you enlighten me what may cause a NullReferenceException in the code below? I tried to create an array of my own (student) class but in vain it seems... using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { public class student { public string name; public byte note; } class Program { static void Main(string[] args) { student[] students = new student[5]; Random rnd = new Random(); for (int i = 0; i Thanx if you have a cure.

Jure · Answer

That's right. Array is simply a list that can store objects/values of custom type. It's up to you then to assign elements. So when you create a new array (using keyword new) all elements are empty at first. If it's an array of objects all elements are empty references - references to nothing. And reference to nothing is null. Consider this: student sample = new student(aaa rand.Next(1 6)); student[] array = new student[5]; array [3] = sample; // student[3] becomes reference to sample array [3].name = bbb; // change sample's name trough that reference Console.WriteLine(sample.name); // outputs sample's name which is now bbb Objects are always considered a reference. For example if you pass an object to a function it won't create new instance (a copy) but will simply pass a reference to that object. So changing the passed object in function's body will actually change the object itself. This is different from passing a variable of type int where only its value is passed.

Jure · Answer

Elements in your array haven't been assigned yet they're all null. One way is to make a constructor for student class that sets note and name member. Put this into student class: public student(string name byte note) { this.name = name; this.note = note; } Then you can write: for (int i = 0; i { students[i] = new student(aaa (byte)rand.Next(1 6)); } Another way is to make name and note into properties (but you don't need to write constructor): Replace public string name; with public string name { get; set; }  and replace public byte note; with public byte note { get; set; } Using the above loop you can now write: for (int i = 0; i { students[i] = new student { name = aaa note = (byte)rand.Next(1 6) }; } The last version is more flexible because you can choose which properties you want to set. Anyway the point is that element(s) must be a reference to an instance of an object (of class student in your case) if you want to use the elements as objects. So you must use keyword new for each element (assuming you want every element to be unique instance).

Suthish Nair · Answer

good one jure...

ldmn · Answer

Thanx Maestro this is really information overload I must learn much it seems. Thanx good byte!

ldmn · Answer

Thanx Jure Ziberna for the thorough info! Really helpful it was. I tried your first method with the constructor and it worked. So as a conclusion arrays of class instances must have 2 new instructions: 1 for creating the whole array and 1 for each element in the array. If I am right... Thanx for much help have fun!