compare 2 keys to get value

Question

I have an arrayList with key which are shown below: 1 2 3 1 2 1 3 3 1 2 3 1 2 3 2 3 1 I have another sortesList with key and value which shown below: 1:4 2:4 3:4 1 2:3 1 3:3 2 3:4 1 2 3:4 if the key in arrayList which is same with the key in sortedlist then will come out the value. my expected output is : 1:4 2:4 3:4 1 2:3 1 3:3 2 3:4 1 2 3:4 2 3 1:4 how i compare this 2 keys and display it in another new sortedList? Hope someone can help me. my coding are shown below: ArrayList arryKey = new ArrayList(); double v; foreach (String key1 in sortList2.Keys) { arryKey.Add(key1); foreach (String key in arryKey) { if (sortList.ContainsKey(key)) { sortList.TryGetValue(key1 out v); richTextBox5.AppendText(key1 +   + v +
); } } }

Vulpes · Answer

I'm surprised it worked at all as you didn't add any elements to the ArrayList! Anyway try this: richTextBox4.Clear(); string AssR = output.Replace(->  ); richTextBox4.AppendText(AssR); String[] split = (output).Split(new string[] { 
	 -> } StringSplitOptions.RemoveEmptyEntries); string[] split2 = new string[split.Length]; for (int i = 0; i { split2[i] = split[i]; richTextBox4.AppendText(split2[i].ToString() + 
); } ArrayList arryKey = new ArrayList(richTextBox4.Lines); // fill arraylist from rtb SortedList sortList2 = new SortedList (); // unless already declared foreach (string key in arryKey) { if (sortList.ContainsKey(key)) { if (!sortList2.ContainsKey(key)) sortList2.Add(key sortList[key]); } } string text =; foreach (string key in sortList2.Keys) { text += String.Format({0}:{1}
 key sortList2[key]); } richTextBox5.Clear(); richTextBox5.AppendText(text);

y s · Answer

Thanks very much. ur coding is very helpful. Once again I am very grateful to you.

y s · Answer

i see. May i know how to change it?

Vulpes · Answer

The problem is this code which is making the value 1 for all keys. foreach (String sort2 in richTextBox4.Lines) { if (!(sortList2.ContainsKey(sort2))) { sortList2.Add(sort2 1); } } If the key has already been added then it will be ignored in the subsequent code and so the value will remain at 1.

y s · Answer

richTextBox4.Clear(); string AssR = output.Replace(->  ); richTextBox4.AppendText(AssR); String[] split = (output).Split(new string[] { 
	 -> } StringSplitOptions.RemoveEmptyEntries); string[] split2 = new string[split.Length]; for (int i = 0; i { split2[i] = split[i]; richTextBox4.AppendText(split2[i].ToString() + 
); } foreach (String sort2 in richTextBox4.Lines) { if (!(sortList2.ContainsKey(sort2))) { sortList2.Add(sort2 1); } } ArrayList arryKey = new ArrayList(); foreach (string key in arryKey) { if (sortList.ContainsKey(key)) { if (!sortList2.ContainsKey(key)) sortList2.Add(key sortList[key]); } } string text =; foreach (string key in sortList2.Keys) { text += String.Format({0}:{1}
 key sortList2[key]); } richTextBox5.Clear(); richTextBox5.AppendText(text); may i know that My code have something error?

Vulpes · Answer

Well you've evidently changed the lists again but even so you should be getting both the key and the correct value (not 1). Are you sure you've copied the code correctly and haven't inadvertently altered something?

y s · Answer

the output is show below but not i wan the values. 1 2:1 2 1:1 1:1 2:1 1 3:1 2 3:1 1 2 3:1 3 1:1 3 2:1 1 3 2:1 2 3 1:1 3:1 for example 1 2 in arrayList is same key with 1 2 in sortedLIst. therefore the value should be 3. e.g. 1 2:3 how i get and display the value?

Vulpes · Answer

The code should be displaying the key/value pairs in the RichTextBox. Is there some other value you want to display?

y s · Answer

thanks for ur help. ur code is very helpful. may i know how to get and display the value?

Vulpes · Answer

Incidentally I forgot to mention that you won't get the elements in the same order using that code because once they're added to the SortedList they're sorted by keys and 1 2 comes before 2 and so on. If you do want to preserve the order then use the following code instead: string text = ; foreach(string key in arryKey) { if(sortList.ContainsKey(key)) { if (!sortList2.ContainsKey(key)) { sortList2.Add(key sortList[key]); text += String.Format({0}:{1}
 key sortList2[key]); } } } richTextBox5.AppendText(text);

Vulpes · Answer

OK try this instead: foreach(string key in arryKey) { if(sortList.ContainsKey(key)) { if (!sortList2.ContainsKey(key)) sortList2.Add(key sortList[key]); } } string text = ; foreach(string key in sortList2.Keys) { text += String.Format({0}:{1}
 key sortList2[key]); } richTextBox5.AppendText(text);

y s · Answer

actually in my arrayList has duplicate keys which shown below: 1 2 1 3 2 1 2 3 1 2 3 3 1 3 2 1 3 2 2 3 1 1 2 1 3 2 1 2 3 1 2 3 3 1 3 2 1 3 2 2 3 1 but in my sortedList just has 1: 4 2: 4 1 2: 3 3: 4 1 3: 3 2 3: 3 1 2 3: 2 if the keys in the arrayList are same with sortedList key then will come out the value. i had try ur code the error is show that the same keys has been added. ArrayList arryKey = new ArrayList(); string text = ; foreach (String key1 in sortList2.Keys) { arryKey.Add(key1); foreach (string key in arryKey) { if (sortList.ContainsKey(key)) { sortList2.Add(key sortList[key]); text += String.Format({0}:{1}
 key sortList2[key]); } } richTextBox5.AppendText(text); }

Suthish Nair · Answer

what error you getting. Also update your correct name instead of short cut.

Vulpes · Answer

Well the code definitely works because I tested it before posting (except I used a MessageBox rather than a RichTextBox) and it produces PRECISELY your expected output. I don't understand the error you're getting unless you're using different data to that shown above and trying to add the same key more than once to a SortedList which isn't allowed.

y s · Answer

i already try ur code but got error. cant show the same keys and values.

Vulpes · Answer

I'd do it something like this (I've included code to load the lists which I needed for testing purposes): string[] strings = { 1 2 3 1 2 1 3 3 1 2 3 1 2 3 2 3 1 }; ArrayList arryKey = new ArrayList(strings); SortedList sortList = new SortedList (); sortList.Add(1 4); sortList.Add(2 4); sortList.Add(3 4); sortList.Add(1 2 3); sortList.Add(1 3 3); sortList.Add(2 3 4); sortList.Add(1 2 3 4); sortList.Add(2 3 1 4); SortedList sortList2 = new SortedList (); string text = ; foreach(string key in arryKey) { if(sortList.ContainsKey(key)) { sortList2.Add(key sortList[key]); text += String.Format({0}:{1}
 key sortList2[key]); } } richTextBox5.AppendText(text);