Dispose pattern in class derivation

Question

Hello everyone For the Dispose pattern here is what MSDN mentioned http://msdn2.microsoft.com/en-us/library/b1yfkh5e(VS.80).aspx -------------------- Implement the dispose design pattern on a base type that commonly has derived types that hold onto resources even if the base type does not. -------------------- Could anyone let me know what means on a base type that commonly has derived types that hold onto resources and the base type does not? Could anyone show some pseudo code please? thanks in advance George

George George · Answer

Thanks Alan Question answered. regards George

Alan · Answer

I think the idea there is that if a programmer is programming against the base class (i.e. assigning references to derived class objects to base class variables) then the dispose pattern will still be available. If the base class implements IDisposable then the public Dispose() method will be callable via a base class variable and will in turn call the virtual protected Dispose(bool) method which does the actual work. However the latter will be the derived class version (not the base class version) because this will be the runtime type of the object. So what it boils down to is: // if base class implements IDisposable and the rest of the dispose pattern Base b = new Derived(); // do some work b.Dispose(); // Compiles and runs OK frees Derived's resources // if base class does not implement IDisposable etc Base b = new Derived(); // do some work b.Dispose(); // does not compile If you're wondering why programmers would want to program against the base class then this is just to have more generic code that can apply to any derived class. A good example in the .NET framework is the abstract Stream class from which various other types of stream are derived.