Error in code

Question

Hi friends I want to know that i have a some lines code that gave this error were the assignments of 9.0 to g. Float g = 9.0; and g = 9.0; float is a floating point number yet the line which assigned the 9 value to f compiles correctly while the assignment of 9.0 to g doesn't! This is definitely counter intuitive! The error is Error 1 Literal of type double cannot be implicitly converted to type 'float'; use an 'F' suffix to create a literal of this type .

Karthik Agarwal · Answer

We cannot even compile a program that might involve a loss of precision. Attempting to (implicitly) convert a double to a float will cause a compile error as you said. We should do one of the following: * Explicitly cast from double to float: float d = (float)3.8; * Use f to indicate that the literal is a float not a double float d = 9.0F;

Karthik Agarwal · Answer

it will work if you write in the following way. float g = 9.0F;