Find third largest integer in an array using only one loop?

Pls follow the steps

1.get it as list 

2. Sort it as descending using lambda

3. Then apply Skip(2).Take(1) => It will skip 0,1 index and take 2 index value.

4. Another option after skip apply firstordefaultvaule. 

Both yield the same result 

Please check below one,

  int largestNumberAtPosion = 3;
  int[] intArray = { 3, 6, 9, 8, 0 };
  var sortedArray = intArray.OrderByDescending(x => x);
  var topNumber = sortedArray.Skip(largestNumberAtPosion - 1).Take(1).FirstOrDefault();

Try this

public class Program
{
	public static void Main()
	{
		int[] unsortedArray = new int[5] {3 ,6, 9, 8, 0};			
				
		Console.WriteLine("Input UnSorted Array: ");	
		Console.WriteLine("------------------------------------------------ ");	
		for( int i = 0; i < unsortedArray.Length; i++)
		{
			Console.WriteLine(unsortedArray[i]);
		}
		
		Console.WriteLine("\n\nThird Largest Element : " + ThirdLargetElement(unsortedArray));	
		
	}		
		
	static int ThirdLargetElement(int[] array)
	{		
		int large = 0, small = 0, mid = 0;	
	 
		for(int i = 0; i < array.Length; i++) 
		{
				if (large < array[i] && mid <= large)
                {
                    small = mid;
                    mid = large;
                    large = array[i];
                }
                else if (mid < array[i] && small <= mid)
                {
                    small = mid;
                    mid = array[i];
                }
                else if (small <= array[i])
                {
                    small = array[i];
                }
		}
		return small;  
	}	
}

OutPut

Input UnSorted Array: 
------------------------------------------------ 
3
6 
9
8
0

Third Largest Element : 6

Try this

int[] array = { 3, 6, 9, 8, 0 };
Array.Sort(array);
int elementCount = 0;
int? thirdLargestNumber = null;
foreach (var element in array)
{
    var temp = array.Skip(elementCount).ToArray();
    if (temp.Length == 3)
    {
        thirdLargestNumber = temp[0];
        break;
    }
    elementCount++;
}
Console.WriteLine($"Third largest number = {thirdLargestNumber}");

public class ThirdLargestInArrayExample{  
public static int getThirdLargest(int[] a, int total){  
int temp;  
for (int i = 0; i < total; i++)   
        {  
            for (int j = i + 1; j < total; j++)   
            {  
                if (a[i] > a[j])   
                {  
                    temp = a[i];  
                    a[i] = a[j];  
                    a[j] = temp;  
                }  
            }  
        }  
       return a[total-3];  
}  
public static void main(String args[]){  

int c[]={3,6,9,8,0};  
int a[]={1,2,5,6,3,2};  
int b[]={44,66,99,77,33,22,55};  
System.out.println("Third Largest: "+getThirdLargest(c,5));  
System.out.println("Third Largest: "+getThirdLargest(a,6));  
System.out.println("Third Largest: "+getThirdLargest(b,7));  
}}  

 

Output :

Third Largest:6
Third Largest:3
Third Largest:66