How can i open the file when windows(c#) datagridview items in are clicked?

Question

Hi everybody I want to know how can we open the file when the items in datagridview are clicked ... I am using xml as datasource in win appln... Hope i ll get my result... Thanks all... With Regards Raman.C

Vimal Kandasamy · Answer

to open a fileadd Process.start(filepath); in cell click event of datagridview like private void StartDataView_CellClick(object sender DataGridViewCellEventArgs e) { Process.Start(filepath); }

Vimal Kandasamy · Answer

if it stored in exact cell where you have clicked means String filepath =dataGridView1.CurrentCell.Value.ToString(); or if it stored in any one cell of clicked row means try String filepath = dataGridView1.CurrentRow.Cells[index].Value.ToString(); here index will be your columnindex 0 or 1 or 2...based on filepath cell column index.

Feroz Khan · Answer

Dear Vimal how can i sort out list box value by modified date in C#.. Regards Feroz

Raman Rajesh · Answer

Thanks a lot vimal.. But how can i get the filepath... suppose i ve stored it in my gridview.. wats d code 2 retrieve that ... Raman.C