How sum of each row 2D array [36]

Question

how sum of each row 2D array [36] Write c# programming to the following: -Initialize two D –array [36]. -Read there values from user. -sum of each row and print the result. -multiplication of each columns and print the result. -print out the array as following. output : 1 2 3 4 5 6 sum= 21 2 6 5 4 9 7 sum= 33 8 7 6 5 9 0 sum= 35 m= 16 m= 84 m=90 m= 80 m= 405 m= 0

Vulpes · Answer

Well it's obviously homework but as it's very easy I'll do it for you this one time: using System; class Test { static void Main() { int[] ia = new int[3 6]; int[] sum = new int[3]; int[] product = new int[6]; for(int i = 0; i for(int i = 0; i { for (int j = 0; j { Console.Write(Value for ia[{0} {1}] :  i j); int.TryParse(Console.ReadLine() out ia[i j]); sum[i] += ia[ij]; product[j] *= ia[i j]; } } // print results Console.WriteLine(); for(int i = 0; i { for (int j = 0; j { Console.Write({0 -8} ia[ij]); } Console.WriteLine( sum = {0} sum[i]); } for(int j = 0; j { Console.Write(m = {0 -4} product[j]); } Console.WriteLine(); Console.ReadKey(); } }

How sum of each row 2D array [3,6]

how sum of each row 2D array [3,6]