How to set status page on my web application in C#?

Question

Hi Friends I ve the application screen like that below departuredate=textbox submit(button) cancel(button) from =textbox to =textbox no.of.days= textbox Lodge = textbox food Bill = textbox daily Allowance = textbox Add(after press the button entire details ll show on My gridview) My requirement is when the user make submit that request details ll go that user reporting to person 1) i want to show the details for user reference to check that status on another page how to do that? 2) before approve the request status shown Fresh in that time user can modify after approve that request status shown Approved edit control can be disable how to do these? give suggestion for two doubts?

Rocky Rocky · Answer

Hi  i need one more help from u i made the condition as per ur guidence for lodging & food bill choosen daily allownce read only. its working fine but when i choose from gridview(edit button entire details ll appear on input screen) blank values of grid returns   for ur reference added screen shot help me?

Iftikar Hussain · Answer

you check condition before display cancel edit delete button for the status column in your page Regards Iftikar

Rocky Rocky · Answer

Hi Friend i need like these ex: sum details when the user given submit means fresh user can edit the details after approved by reporting to person the user doesn't allow enter cancel button

Iftikar Hussain · Answer

Hi Simple have one status column in your travel table. While first time creating the travel request insert the status value as 'Fresh' along with your other column value into travel request table. Then while updating means approving the request update the column value to 'Approved' and set 'Reject' in case if you have reject option. Regards Iftikar