Is this possible in .NET .Please reply ?

Question

Class A() { function Test() { Msg(Base Class); } } Class B Inherits from A() { { Msg(“Child Class”); } } A a = new B() Can this is possible. If Yes what msg it will show and why?

Alan · Answer

Yes it's possible to write something like that in C#. Here it is as a runnable console application (ignore the compiler warning you get): using System; class A { public void Test() { Console.WriteLine(Base Class); } } class B: A { public void Test() { Console.WriteLine(Child Class); } } class Test { static void Main() { A a = new B(); a.Test(); Console.ReadLine(); } } If you run this 'Base Class' will be printed to the console because A's version of Test() is called. In other words it's the compile time type of 'a' that determines which version of Test() is called (i.e. A) not the runtime type (i.e. B). Now change the program to the following: using System; class A { public virtual void Test() { Console.WriteLine(Base Class); } } class B: A { public override void Test() { Console.WriteLine(Child Class); } } class Test { static void Main() { A a = new B(); a.Test(); Console.ReadLine(); } } This time 'Child Class' gets printed to the console. Because we've made Test() into a virtual method it's the runtime type of 'a' (i.e. B) which now determines which version of Test() gets called. EDIT: Sorry for forgetting to insert 'virtual' and 'override' in the second version of the program!

Rohti Ambani · Answer

I think U have missed a Virtual keyword? Please place this word in the example.