more clarification please in C programming

Question

there is issue with my codes: #include #include char s[80] int i; int main (){ strcpy(s hi there); i=0; while(s [i] !='&'){ i ++; } i ++; while(s[i] !='&'){ i++; } printf( i=%d
i); }

Vulpes · Answer

Yes if there were no ampersands in memory it would loop 'for ever' . On the second point there are number of issues but this should compile and print something sensible: #include void triangle (void); int main () { printf(Hello World
); triangle(); printf(n:
); return 0; } void triangle (void){ printf( *
); printf( ***
); printf(******
); }

sami sam · Answer

so that why I got empty black screen even after putting the semi-colon.

sami sam · Answer

And these codes as well. #include void triangle (void); int main () { print(Hello World); } triangle(); printf(n:
); void triangle (void){ printf(*
); printf(***
); printf(********
); }

Vulpes · Answer

There's a missing semi-colon after char s[80] but otherwise you need to test in your while loops for a character which is actually present at least twice in your string such as 'h' or 'e' in this example. If you don't do this then you'll get a silly answer as the while loops keep on iterating until they find a '&' in memory.