serialPort1.WriteLine error

Question

Hello everyone.

I use virtual COM ports for testing my program. I want to Serial Write with COM8 and Serial read with COM9. When a want to write the values in textbox1, i get this error:

How do i get rid of this ?

Thanks in advance

Osman Esen · Answer

Thanks for checking :)

Vulpes · Answer

No, the code looks OK to me.

Osman Esen · Answer

Is there anyting wrong with the "write" and "read" part ?. I have made a virtual com pair with COM8 and COM9

Vulpes · Answer

It's an unusual error but see if there's anything in this thread which helps: http://stackoverflow.com/questions/5565007/serialport-open-ioexception-the-parameter-is-incorrect

Osman Esen · Answer

Here is my code: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Threading.Tasks; using System.Windows.Forms; using System.IO.Ports; namespace Flowerpod_User_Interface { public partial class Form1 : Form { public Form1() { InitializeComponent(); // show list of valid COM ports foreach (string s in System.IO.Ports.SerialPort.GetPortNames()) { comboBox1.Items.Add(s); } } private void textBox1_TextChanged(object sender, EventArgs e) { } private void Form1_Load(object sender, EventArgs e) { } private void button1_Click(object sender, EventArgs e) { if (serialPort1.IsOpen) { serialPort1.WriteLine(textBox1.Text); } } private void comboBox1_SelectedIndexChanged(object sender, EventArgs e) { } private void Connect_Click(object sender, EventArgs e) { if (!serialPort1.IsOpen) { serialPort1.PortName = comboBox1.SelectedItem.ToString(); serialPort1.Open(); textBox3.Text = "Open"; } } private void textBox3_TextChanged(object sender, EventArgs e) { } private void textBox2_TextChanged(object sender, EventArgs e) { } private void button3_Click(object sender, EventArgs e) { Random slumpGenerator = new Random(); // Or whatever limits you want... Next() returns a double int tal = slumpGenerator.Next(1000, 10000); textBox1.Text = tal.ToString(); } private void textBox4_TextChanged(object sender, EventArgs e) { } private void serialPort1_DataReceived(object sender, SerialDataReceivedEventArgs e) { } private void button4_Click(object sender, EventArgs e) { if (!serialPortRead.IsOpen) { serialPort1.PortName = "COM9"; serialPortRead.Open(); textBox4.Text = serialPortRead.ReadLine(); } } } }

serialPort1.WriteLine error

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Answers (5)