Sum and split array like below.

Question

int arr[]={ 123 456 789  987 654 321 9 87 654 3 21 123 456 789 } int innergroup=3;//vary from 12..n int outergroup=9; //vary from 12..n int mplit=2; //vary from 12..n res[0]=29 //1+4+7+9+6+3 res[1]=30 //2+5+8+8+5+2 res[2]=30 //3+6+9+7+4+1 res[3]=30 //9+6+3+1+4+7 res[4]=30 //8+5+2+2+5+8 res[5]=30 //7+4+1+3+6+9 res[0]=first element of inner ingroup1 of split1+first element of inner ingroup2 of split1+first element of inner ingroup3 of split1+first element of inner ingroup1 of split2+first element of inner ingroup2 of split2+first element of inner ingroup3 of split2 and likewise

Tapan Patel · Answer

class Program { static void Main( string [] args) { SplitTheArrayAndDoSumOfEveryOtherThirdNumber(); } private static void SplitTheArrayAndDoSumOfEveryOtherThirdNumber( int split = 4) { //int[] arr = { 1 2 3 4 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 4 }; int [] arr ={ 123456789 987654321 987654321 123456789 }; int outergroup = 9; int factor = arr.Length / outergroup; Console.WriteLine(arr.Length); //int split = 2; List int []> splitted = new List int []>(); for ( int i = 0; i { splitted.Add( new int [outergroup]); for ( int j = i * outergroup; j { (splitted[i])[j - (i * outergroup)] = arr[j]; } Console.WriteLine(); } List int > sums = new List int >(); int innergroup = 3; for ( int i = 0; i { for ( int y = 0; y { int sum = 0; for ( int j = y; j { sum += (splitted[i])[j] + (splitted[i + 1])[j]; } sums.Add(sum); } } foreach ( int sum in sums) { Console.WriteLine(sum); } } }