TextBox Properties and setting initial values to textBoxes

Question

Hi

I have a problem with 3 textBoxes. I need to set an inital value (texts) for each textBox
and when I need to change / rewrite a value in one of the textBoxes then the applicaiton will allow me to do so.

I tried to set the text for each textBox from the TextBox properties >> Text. but this doesn't display the
value in the textBox. and if I set the following:

private void TextBox1_TextChanged(object sender, EventArgs e)

{
TextBox1.Text = "InitialText1";
}

private void TextBox2_TextChanged(object sender, EventArgs e)

{
TextBox1.Text = "InitialText2";
}

private void TextBox3_TextChanged(object sender, EventArgs e)

{
TextBox1.Text = "InitialText3";
}

This will show the value in the textBox but will not allow me to change it at the run time.

What shall I do?

Vulpes · Answer

Although as Princy said you can set the Text properties of the TextBoxes initially in the Form's constructor or in Form_Load there's something seriously wrong if you can't successfully set these properties in the Properties Box. When you do this the initial values should show up immediately in the designer. So if I were you I'd try and get to the bottom of this before you do anything else as whatever's causing the problem might come back and bite you later. It might be an idea to delete these TextBoxes from the designer add them back again and see if you can set their Text properties then. I'd also remove the TextChanged handlers via the Properties Box as you don't need these unless you need to be notified when the Text property is subsequently changed.

Jyothi · Answer

You can use Ajax watermark extender Something like this ajaxToolkit : TextBoxWatermarkExtender ID =twFname runat =server TargetControlID =txtFirstname WatermarkText =Enter Your First Name />

Princy Gupta · Answer

i guess you can set the initial values in the constructor and then try and then when you load your window the default text would be visible and you would be also able to change the same

Munesh Sharma · Answer

use keypress event handler like that textBox3.KeyPress += new KeyPressEventHandler(textBox3_KeyPress);