Introduction
In C Sharp (C#) we can have three types of
parameters in a function. The parameters can be In parameter (which is not
returned back to the caller of the function), out parameter and ref parameter
(where by a reference to the variable is ed back).
The first thing that we will take a look at, is
the out and ref modifiers. C#, and other languages as well, differ between two
parameters: "by value" and "by reference". The default in C# is "by value",
which basically means that when you on a variable to a function call, you
are actually sending a copy of the object, instead of a reference to it. This
also means that you can make changes to the parameter from inside the function,
without affecting the original object you ed as a parameter.
Consider the following example:
using
System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Text;
namespace
simplevalue
{
class Progra
{
static
void Addvalue(int
val)
{
val++
}
static void
Main(string[] args)
{
int
value = 10;
Addvalue(value);
Console.WriteLine(value);
Console.Read();
}
}
}
Output: 10
We create an integer, assign the number 10 to it,
and then we use the Addvalue() method, which should add 1 to the number. But
does it? No. The value we assign to number inside the function, is never carried
out of the function, because we have ed a copy of the number value instead
of a reference to it. This is simply how C# works, and in a lot of cases, it's
the preferred result. However, in this case, we actually wish to modify the
number inside our function. Enter the ref and out keyword:
The out and ref keyword are looks quite similar in
nature. Both parameters are used to return back some value to the caller of the
function. But still there is a small but important difference between them. Both
of the parameter type has been kept in the C# language for specific scenario.
"out" keyword
The out parameter can be used to return the values in the same
variable ed as a parameter of the method. Any changes made to the parameter
will be reflected in the variable.
The out keyword causes arguments
to be ed by reference. This is similar to the refkeyword, except that ref
requires that the variable be initialized before being ed. To use an
out parameter, both the method definition and the calling method must
explicitly use the out keyword.
For example:
using System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Text;
namespace
outexample
{
class Program
{
static void
value(out int
val)
{
val = 20;
}
static void Main(string[]
args)
{
int value;
value(out value);
Console.WriteLine(value);
Console.Read();
}
}
}
Output: 20
When we use the out parameter, The program calling
the function need not assign a value to the out parameter before making the call
to the function. The value of the out parameter has to be set by the function
before returning the value.
"ref" keyword
The ref keyword on
a method parameter causes a method to refer to the same variable that was ed
as an input parameter for the same method. If you do any changes to the
variable, they will be reflected in the variable.
The ref keyword is similer to out
keyword but ref requires that the variable be initialized before being ed.
For example
using
System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Text;
namespace
outexample
{
class Program
{
static void
value(ref int
val)
{
val = 20;
}
static void Main(string[]
args)
{
int value;
value(ref value);
Console.WriteLine(value);
Console.Read();
}
}
}
when we build this code it
will fire an error "use of unassigned local variable 'value' " the resion is
behind that the ref requires that the variable be initialized before being
ed.
To run above program properly just initialized the value (variable).
For example
using
System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Text;
namespace
outexample
{
class Program
{
static void
value(ref int
val)
{
val = 20;
}
static void Main(string[]
args)
{
int value = 10;
value(ref value);
Console.WriteLine(value);
Console.Read();
}
}
}
Output: 20
Some more useful facts about ref and out keyword
The ref and out keywords are treated
differently at run-time, but they are treated the same at compile time.
Therefore methods cannot be overloaded if one method takes a ref
argument and the other takes an out argument. These two
methods, for example, are identical in terms of compilation, so this code will
not compile
class
Program
{|
// compiler error CS0663: "cannot define
overloaded
// methods that differ only on ref and
out"
public
void value(out
int i) { }
public void
value(ref int
i) { }
}
Overloading can be done,
however, if one method takes a ref or out
argument and the other uses neither, like this:
class
Program
{
public void
value(int i) { }
public void
value(out int
i) { }
}
Declaring an out method is useful
when you want a method to return multiple values. A method that uses an
out parameter can still a variables as a return type (see return) but
it can also return one or more objects to a calling method as out
parameters. This example uses out to return three variables
with a single method call. Note that the third argument is assigned to null.
This allows methods to return values optionally.
using System;
using
System.Collections.Generic;
using
System.Linq;
using
System.Text;
namespace
outexample
class Program
{
static void
value(out int
i,out string
s1,out string
s2)
{
i=20;
s1="I've been returned";
s2=null;
}
static void
Main(string[] args)
{
int v;
string str1,str2;
value(out v,out
str1,out str2);
Console.WriteLine(v +"
" + str1 +" "+ str2);
Console.Read();
}
}
}
Output: 20 I've been returned
Properties are not variables and therefore cannot
be ed as out parameters.
Final conclusion:
The out and the ref parameters are used to
return values in the same variables, that you an argument of a method.
These both parameters are very useful when your method needs to return more than
one values.