Alphabet Pattern 'C' in Python

Code:

str="";
for Row in range(0,7):
    for Col in range(0,7):
        if ((Col == 1 and (Row != 0 and Row != 6)) or ((Row == 0 or Row == 6) and (Col > 1 and Col < 5)) or (Col == 5 and (Row == 1 or Row == 5))):
            str=str+"*"
        else:
            str=str+" "
    str=str+"\n"
print(str);

Output: