Alphabet Pattern 'J' in Python

Code:

str="";
for Row in range(0,7):
    for Col in range(0,7):
        if ((Col == 4 and Row != 6) or (Row == 0 and Col > 2 and Col < 6) or (Row == 6 and Col == 3) or (Row == 5 and Col == 2)):
            str=str+"*"
        else:
            str=str+" "
    str=str+"\n"
print(str);

Output: