Alphabet Pattern 'U' in Python
In this Blog I am printing pattern 'U' using Python.
Code:
- str="";
- for Row in range(0,7):
- for Col in range(0,7):
- if (((Col == 1 or Col == 5) and Row != 6) or (Row == 6 and Col > 1 and Col < 5)):
- str=str+"*"
- else:
- str=str+" "
- str=str+"\n"
- print(str);
Output: