------------ Coding is all what I know -------------
Being a Microsoft technology developer, Reading XML is a very basic task, to read. Write or transfer data. Whether it be RSS feeds or Database data access, everywhere its all XML , There are a lot of ways to read XML using XPATH language XPATHNAVIGATOR, browsing through each nodes and finally extracting data. This is so complex and of course lot of coding. I have suggested an easy and efficient way to READ XML
String xmlURL = “http://www.microsoft.com/feeds/msdn/en-us/rss.xml “; // Specify any RSS Feed Url
XmlReader xReaderResult = null;
try
{
xReaderResult = XmlReader.Create(xmlUrl, settings);
doc.Load(xReaderResult); // Loading the XML Document
}
catch (XmlException ex)
{
throw new Exception("error RSS feed is not well formed: " + ex.Message);
}
XmlNode nRoot = doc.DocumentElement;
XmlNodeList xNodeList = nRoot.SelectNodes("channel/item"); // Selecting the Nodes in XML in this case for RSS feeds
XmlTextReader xReader;
// Dumping the RSS Data into Datatable
for (int x = 0; x < xNodeList.Count; x++)
{
xReader = new XmlTextReader(xNodeList.Item(x).OuterXml, XmlNodeType.Element, new XmlParserContext(null, null, null, XmlSpace.None));
ds.ReadXml(xReader, XmlReadMode.InferSchema);
}
dt = ds.Tables[0];
dt.TableName = this.Title;
After Getting the XML data into the Datatable you can extract the data and get each of the node data or bind it to a Grid View and display the data in Grid Fashion
Extracting the XML data from datatable
int k = 0;
foreach( Datarow oDr in dt.Rows)
{
titleArray[k] = oDr[“Title”]; // Extract each Node
pubdateArray[k] = oDR[“pubdate”];
k++;
}
Binding it to Gridview
oGridView.Bind(dt);
Thanks Enjoy !!!!
Joe