Array random numbers for doubles

Question

so far i have this: i couldn't figure out how to make an array.
Generate button, i called it BTN_generate
public partial class Form1 : Form
{
Random random = new Random();
double dtotal = 0;
public Form1()
{
InitializeComponent();

}

private void BTN_generate_Click(object sender, EventArgs e)
{
int irandom = random.Next(0, 100);
double drandom = random.NextDouble();

dtotal = irandom + drandom;
textBox1.Text = dtotal.ToString("0.00");
}
}

and i tried without double drandom = random.NextDouble();
public partial class Form1 : Form
{
int[] iArray = new int[20];

Random rNumber = new Random(101);but my code didn't work

private void BTN_generate_Click(object sender, EventArgs e)
{
for (int i = 0; i < iArray.Length; i++)
{
iArray[i] = rNumber.Next(101);
}

Console.WriteLine();
foreach (int iValue in iArray)
{
textbox1.Text = iValue.ToString();
}
}
}

this one is just giving me one number.

Vulpes · Answer

You can do that within a method as follows: int numElements = random.Next(5 11); // excludes endpoint iArray = new int[numElements]; If you want to do it at form level then you'll need to make both 'random' and 'numElements' into static fields so that they will have been initialized before the instance field iArray is created. Otherwise you'll get a compiler error: static Random random = new Random(); static int numElements = random.Next(5 11); // excludes endpoint int[] iArray = new int[numElements];

Javeed M Shaikh · Answer

Hi Jonathan Replace your line : textbox1.Text = iValue.ToString(); with this line: textbox1.Text += iValue.ToString() +  ; Please do not forget to mark Accepted Answer.

Jonathan Crispe · Answer

thank you... Another question: how make int[] iArray = new int[20]; random i mean instead of exact 20 how can make it random(5 10);