Convert an int to a int[]

Question

Hi
I'm using the same method for user input. So I have the same method for reading an int and to read in values to a int[] - array. I get a error saying can't convert type int to int[]. I can't use any other method I have to use the same method for collecting data for both the int and the array. Is there any way to solve this.
Greatfull for the help.

Akkiraju Ivaturi · Answer

The problem is here: int count = numberOfSalaries - 1;//This should be int Count = numberOfSalaries. int[] salaries = new int[count]; Let say that I enter number of salaries = 2 Then count = 2-1=1 Now your array Salaries length is int[] Salaries = new int[1] i.e. 1 but your loop is for (int i = 0; i { } so here there are two iterations for i=01 But your array can accomodate only one value as its length is 1 Salaries[0] = will take your value from command prompt Salaries[1] = This will give you index outside bounds of the array. Let us know if you have any questions.

Vulpes · Answer

The problem is this line: int[] salaries = new int[count]; which should be: int[] salaries = new int[count + 1];

Frohikki · Answer

Thank you for the replies. It seems to work fine except that i get an error: index outside the bounds of the array. How can that be? class Program { static void Main(string[] args) { int numberOfSalaries = (int)ReadInt(false Hur många löner vill du mata in:  0); Console.WriteLine(); int[] salaries; salaries = (int[])ReadInt(true Mata in lön:  numberOfSalaries); ProcessSalaries(salaries); } static object ReadInt(bool isArray string Prompt int numberOfSalaries) { while (true) //Loopen möjliggör att användaren får fler inmatningsmöjligheter { try { if (isArray == true) { int count = numberOfSalaries - 1; int[] salaries = new int[count]; for (int i = 0; i { Console.Write(Prompt); salaries[i] = int.Parse(Console.ReadLine()); } return salaries; } else { Console.Write(Prompt); int value = int.Parse(Console.ReadLine()); if (value { Console.BackgroundColor = ConsoleColor.Red; Console.ForegroundColor = ConsoleColor.White; Console.WriteLine(
Beräkningen måste innehålla minst två löner
); Console.ResetColor(); } else { return value; } } } catch //Fångar felinmatningar { Console.BackgroundColor = ConsoleColor.Red; Console.ForegroundColor = ConsoleColor.White; Console.WriteLine(
Fel inmatning endast heltal är tillåtna. Var god försök igen.
); Console.ResetColor(); } } }

Akkiraju Ivaturi · Answer

As specified by Vulpes IsArray property let you know whether the type you are passing is an integer or int[]. int[] array = { 1 2 3 4 }; int simpleVariable = 45; Type t1 = array.GetType(); Type t2 = simpleVariable.GetType(); Console.WriteLine({0} is an array: t1.IsArray); Console.WriteLine({0} is an array: t2.IsArray);

Vulpes · Answer

Try this: using System; class Test { static void Main() { Console.WriteLine(Inputting a single number ...
); int num = (int)GetInput(false); Console.WriteLine(
The number input is {0}
 num); Console.WriteLine(Inputting an array of numbers ...
); int[] nums = (int[])GetInput(true); Console.WriteLine(
The numbers input are : 
); foreach(int n in nums) Console.Write({0}  n); Console.WriteLine(); Console.ReadKey(); } static object GetInput(bool isArray) { if (!isArray) { Console.Write( Enter number : ); int num = int.Parse(Console.ReadLine()); return num; } else { Console.Write( Enter how many numbers to be input : ); int count = int.Parse(Console.ReadLine()); int[] nums = new int[count]; Console.WriteLine(); for(int i = 0; i { Console.Write( Enter number {0} :  i + 1); nums[i] = int.Parse(Console.ReadLine()); } return nums; } } }