Convert array string into integer

Question

This program has to finds whether a book dealer carries a requested book. When using BinarySearch() method both argument inside the parenthesis should be in integer.

How to convert string array ("books") into integer array.

using System;
public class DebugSix04
{
public static void Main()
{
String[] books = { "Rich Dad", "Poor Dad", "Catch-22", "Harry Potter", "Programming Using C#", "Wizard of Oz", "The Deep" };

Console.Write("What book are you looking for? ");

int enterBookName = Convert.ToInt32(Console.ReadLine());

int x = Array.BinarySearch(books, enterBookName);

if (x > 0)
Console.WriteLine("{0} not found", enterBookName);
else
Console.WriteLine("Yes, we carry {0}", enterBookName);
}
}

Vulpes · Answer

It's not in fact the case that any of the parameters to Array.BinarySearch need to be an integer (at least for the overloads which are normally used) though the return value is always an integer which represents the index of the item if found. If the item is not found then the method returns a negative integer. Also the array needs to be sorted first before this method can be used. So I think you can do it like this - I've made the search case insensitive which would be normal when looking for book titles: using System; using System.Collections; //needed to do case insensitive search public class DebugSix04 { public static void Main() { String[] books = { Rich Dad Poor Dad Catch-22 Harry Potter Programming Using C# Wizard of Oz The Deep }; IComparer comparer = new CaseInsensitiveComparer(); Array.Sort(books comparer); Console.Write(What book are you looking for? ); string enterBookName = Console.ReadLine(); int x = Array.BinarySearch(books enterBookName comparer); if (x Console.WriteLine({0} not found enterBookName); else Console.WriteLine(Yes we carry {0} books[x]); } }

Maha · Answer

Thank you for your help.

Vulpes · Answer

Well a static method of the Array class has no instance associated with it. You therefore have to pass it one as an argument. I've altered the code so that the compiler will now choose the Array.BinarySearch (T[] T) overload where T is 'int'. Notice that it's not necessary to specify the generic type parameter here - it will still work fine if you omit it. This is because the compiler will infer the type to be int as zip is an int array and zipcode is a scalar int variable: using System; namespace BinarySearchDemo { class Program { static void Main(string[] args) { int[] zip = new int[5] { 1000 2000 3000 4000 5000 }; Console.Write(Enter a ZIP code ); string enter = Console.ReadLine(); int zipCode; int.TryParse(enter out zipCode); // zip will be 0 if enter is invalid int num = Array.BinarySearch (zip zipCode); // is optional here if (num Console.WriteLine(Zip is not found); else Console.WriteLine(Array position is {0} num); Console.ReadKey(); } } }

Maha · Answer

Thank you for your explanation. Could you explain what is meant by This is necessary because it's a static method of the Array class . This program has been altered to take two different types in BinarySearch() method. Please use T[] and correct it. using System; namespace BinarySearchDemo { class Program { static void Main(string[] args) { int[] zip = new int[5] { 1000 2000 3000 4000 5000 }; Console.Write(Entre a ZIP code ); string enter = Console.ReadLine(); int num = Array.BinarySearch(zip enter); if (num Console.WriteLine(Zip is not found); else Console.WriteLine(Array position is {0} num); Console.ReadKey(); } } }

Vulpes · Answer

Well if you study the overloads there are two types: 1. Those which take an Array as the first parameter. 2. Those which take a T[] as the first parameter where T is a generic type parameter. The first group are weakly typed and are not bothered at compile time what the type of the array is. Consequently if you try to search for an element which is not compatible with the type of the array you will get an exception. The second group are strongly typed and the compiler infers the type of T (and hence the type of element to look for) from the type of the array that is being passed to it. The compiler will choose these overloads rather than the others when it can.

Maha · Answer

That means any type of array is considered only as an array (not the type it belongs to) inside the parenthesis of BinarySearch() method. I wish to know whether my understanding is correct.

Vulpes · Answer

Here's a list of the overloads of the Array.BinarySearch method: http://msdn.microsoft.com/en-us/library/system.array.binarysearch.aspx As you'll see there isn't one which takes an int as its first parameter. In fact all of them take the array itself as the first parameter. This is necessary because it's a static method of the Array class. The first and second parameters are always of different types.

Maha · Answer

Thank you for your help. I wish to know whether both arguments inside the parenthesis of BinarySearch() method can be different types. That means for example: BinarySearch(int string)