double to decimal place

Question

I want to show the decimal place.. double mper = m / 100; double mperdec = m % 100; lbllocalper.Text = mper + . + mperdec + %; if m is 2 mper will be 0.0 and mperdec will be 2. But if I show in lbllocalper  it becomes 0.2! I actually want 0.02! If there is any solutions for me please cmt in my post. Thanks a lot for viewing my post.

Upendra Pratap Shahi · Answer

use this- int m = 2; double mper = m / 100; double mperdec = m % 100; lbltest.Text = mper + .0 + mperdec.ToString(00) + %;

Pankaj Kumar Choudhary · Answer

Hello @Soe you can try this code int m; double mper; double mperdec; int len; string str; Console.WriteLine(Enter value of M); m= int.Parse(Console.ReadLine().ToString()); mper = m / 100; mperdec = m % 100; len = m.ToString().Length; if (len == 1) str = mper + . + 0 + mperdec + %; else str = mper + . + mperdec + %; lbllocalper.Text=str;

Pankaj Kumar Choudhary · Answer

Hello @Soe you can try this code int m; double mper; double mperdec; int len; string str; Console.WriteLine(Enter value of M); m= int.Parse(Console.ReadLine().ToString()); mper = m / 100; mperdec = m % 100; len = m.ToString().Length; if (len == 1) str = mper + . + 0 + mperdec + %; else str = mper + . + mperdec + %; Console.WriteLine(str); Console.ReadLine();

Asp.Net Hein · Answer

Upendra Pratap Shahi  u give me childish answer.. I want general answer for dynamic value. Your answer is even child know that.....

Upendra Pratap Shahi · Answer

int m = 2; double mper = m / 100; double mperdec = m % 100; lbltest.Text = mper + .0 + mperdec + %;