Dynamic data type

Question

In this following example dynamic data type is behaving in a contradictory manner. Please explain the reason.

Dynamic data type multiplying two variables in the 1st output and adding two variables in the 2nd output. Problem is highlighted.

using System;
class Program
{
static void Main(string[] args)
{
dynamic d1, d2;
d1 = "A";
d2 = 1;
Console.WriteLine(d1 + d2);//A1

d1 = 10.01;
d2 = 1;
Console.WriteLine(d1 + d2);//11.01

Console.ReadKey();
}
}

Maha · Answer

Thank you for your explanation.

Vulpes · Answer

For the first pair of values the CLR infers that the type of d1 is string because a string is being assigned to it. It also infers that the type of d2 is int because an int is being assigned to it. When you add an int to a string you concatenate the string with the 'string value' of the former. In other words it's like computing A + 1 which is A1. For the second pair of values the CLR infers that the type of d1 is double because a double is being assigned to it. As before it infers the type of d2 to be int. When you add an int to a double you get a double and the rules of floating point arithmetic therefore give 10.01 + 1 = 11.01.