File Write Problem

Question

Hello! What's wrong for my listed coding? I can create a file with the inputted file name but how can I add sContent into my created file? Please give me reply asap. Thanks! //Save File private void btnSave_Click(object sender System.EventArgs e) { string sCheck=txtFileName.Text; if(sCheck.Length !=0) { string strLog=txtFileName.Text; FileStream fw = new FileStream(strLog +. + dat FileMode.CreateNew FileAccess.Write); string sContent=How to add this message into the created file; fw.Write(sContent); fw.Close(); MessageBox.Show(File Created and Written successfully!FinishedMessageBoxButtons.OKMessageBoxIcon.Information); } else { MessageBox.Show(File Name is empty cannot save file!ErrorMessageBoxButtons.OKMessageBoxIcon.Error); } }

softairhk · Answer

Hello! Mike Can you write an example for me to explain Chornberger stated method? Thanks!

jcity444 · Answer

1) You can add each line using StreamWriters WriteLine method. sw.WriteLine(sContent1); sw.WriteLine(sContent2); 2) appending data can be done by constructing the stream writer with the second paramter set to true and then using Write and WriteLine. The second parameter puts the file in append mode. StreamWriter sw = new StreamWriter(path + \ + strLog + .dat true); 3) I think you'll need to add the header info at the same time you do the content otherwise you'll need to read the file into a string using StreamReader parse out the header info and parse out the content separately (using regular expressions) form a new string and write out back out using StreamWriter 4) Similar to part 3. First use StreamReader to read your file and then use the header info to form new files and place the content in them. Below is a quick mock up of how I think it would go: StreamReader sr = new StreamReader(path + \ + strLog + .dat); while (sr.Peek() >= 0) { string nextLine = sr.ReadLine(); if (nextLine.Trim()[0] == [) { string header = nextLine.Trim().Substring(1 nextLine.Trim().Length - 2); StreamWriter sw = new StreamWriter(txt + header + .Text); nextLine = sr.ReadLine(); sw.WriteLine(nextLine.Trim()); sw.Close(); } } Hope this helps! If you don't need to do it this way I agree with chornberger use the built in xml functions or serialization functions its easier and adheres more to standard than the old ini file style ;) -Mike G.

chrishornberger · Answer

Soft do you *need* it in that format? It would be a simple thing to either: 1) encase it in some structure a la a hashtable and binary serialize it out 2) wrap it in stuctured xml and write it out

softairhk · Answer

Dear Mike Thanks for your help. Your coding is work. But I got new questions want to ask you? 1) How to put the content in different line? e.g. string sContent1=Content of line 1; string sContent2=Content of line 2; string sContent=sContent1 + sContent2; I have tested the sContent2 add to the end of sContent1 I want to them be added as following: test.dat open in Notepad will look like this: Content of line 1 Content of line 2 2) How to append new content into the existing created file? e.g. string sContent3=Add new content; 3) How to add header for the content? e.g. I want my created test.dat open in Notepad will look like this: [Content 1] Content of line 1 [Content 2] Content of line 2 [Content 3] Add new content 4) How I can base on the header to open test.dat and read the data of Content1 Content2 and Content3 to display in txtContent1.Text txtContent2.Text and txtContent3.Text? Please give me reply asap. Thanks!

jcity444 · Answer

this seems okay to me. Not sure why its not working but I recommend you use StreamWriter. string path = Application.ExecutablePath; string sContent=How to add this message into the created file; path = path.Substring(0 path.LastIndexOf(\)); StreamWriter sw = new StreamWriter(path + \ + strLog + .dat false); sw.Write(sContent); sw.Close(); -Mike