Mathematical Operator in an expression

Question

I am using the expression below to calculate the distance however the parser is unable to process this expression Distance = (1/2) * (GRAVITATIONAL_FORCE) * (time *2) If i use the above expression as below it works. Distance = FRACTION * GRAVITATIONAL_FORCE * (time * 2) FRACTION = 0.5 I have tried to assign FRACTION = (1/2) and use FRACTION as variable in above expression it does not work either. Please suggest what is wrong with the first expression. Also is there a function for a square of a number? in above expression time is a variable that need to be square I have been writing expression as (time *time) or (time * 2)

Bikesh Srivastava · Answer

Distance = ((double)1/ (double) 2) * (GRAVITATIONAL_FORCE) * (time *2)

Tapan Patel · Answer

The reason behind is when you say 1/2 compiler tries for the operation considering the return value to be assigned will be of type integer and hence 1/2 results in 0 as they are of type ints . In order to correct it you can either cast 1 to double and 2 to double and then use it like Distance = ((double)1/ (double) 2) * (GRAVITATIONAL_FORCE) * (time *2) or just cast your constants to double data types by Distance = (1.0/2.0) * (GRAVITATIONAL_FORCE) * (time *2) Please mark it as answer if it addresses the issue.

Midhun T P · Answer

Hi Please try below code- Distance = (1.0/2.0) * (GRAVITATIONAL_FORCE) * Math.Pow(time2)