Multi selected listbox values get in label

Question

Hi

How to get listbox multiple selected values in label or string.
I have bind data from table in listbox then when i select multi values then this display in label or string
when i try get values in label then display System.Data.Dataview multi time
my code

for (i = 0; i < lstcsuspectcode.SelectedItems.Count; i++)
{

label18.Text = label18.Text + " " + lstcsuspectcode.SelectedValue;

}

Abdullah Munshi · Answer

Finally here is the solution. string s = ; foreach (DataRowView row in listBox1.SelectedItems) { s = s +   + row.Row[ name ].ToString(); } label1.Text = s; ================ Replace  name  with your column name that you display in listbox.

Suthish Nair · Answer

another sample... AutoPostBack=true Height=39px onselectedindexchanged=ListBox1_SelectedIndexChanged Width=85px> 1 2 3 4 5 6 protected void ListBox1_SelectedIndexChanged(object sender EventArgs e) { foreach (int item in ListBox1.GetSelectedIndices()) { lbl.Text += ListBox1.Items[item].Text +  ; } }

Satyapriya Nayak · Answer

Hi shubhangi Try this... using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.Data.OleDb; namespace Listbox2 { public partial class Form1 : Form { string ConnectionString = System.Configuration.ConfigurationSettings.AppSettings[dsn]; OleDbCommand com; OleDbDataAdapter oledbda; string str; DataSet ds; DataTable dt; public Form1() { InitializeComponent(); } private void Form1_Load(object sender EventArgs e) { OleDbConnection con = new OleDbConnection(ConnectionString); con.Open(); str = select * from emp; com = new OleDbCommand(str con); oledbda = new OleDbDataAdapter(com); ds = new DataSet(); oledbda.Fill(ds emp); dt = ds.Tables[emp]; int i; for (i = 0; i { listBox1.Items.Add(dt.Rows[i].ItemArray[0]); } con.Close(); } private void button1_Click(object sender EventArgs e) { int i; for (i = 0; i { label1.Text = label1.Text +   + listBox1.SelectedItem.ToString(); } } } } Thanks

Piyush Chandrala · Answer

Thanks For Share This Code. Above All Code Not Work But Your Code Is Working. Again Thank U.

shubhangi khandale · Answer

Hi sir we are use windows application and GetSelectedIndices() this method in web

shubhangi khandale · Answer

same error (System.data.DatarowView display in label because i bind list from db) i think when bind data from table then we use selectedvalue property..

Abdullah Munshi · Answer

Here is the code for Windows Forms; string s = ; foreach (object item in listBox1.SelectedItems) { s = s+ + item.ToString(); } label1.Text = s; ====== That previous code was for webapplication. So it gave error missing assembly reference. Try this code.

shubhangi khandale · Answer

Hi All can u give me other solution for my post. i have design form in this form course listbox which bind form coursetable. when student fill this form he can select multi course from listbox then display in label which selected courses so any other solution for this......... plz

shubhangi khandale · Answer

error in ListItem (missing assembly ref)

shubhangi khandale · Answer

have bind listbox from database and if i use this code then display in label System.Data.Dateview multi time

Satyapriya Nayak · Answer

Hi shubhangi Try this... using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace WindowsFormsApplication6 { public partial class Form1 : Form { public Form1() { InitializeComponent(); } private void Form1_Load(object sender EventArgs e) { listBox1.Items.Add(a); listBox1.Items.Add(b); listBox1.Items.Add(c); listBox1.Items.Add(d); } private void button1_Click(object sender EventArgs e) { int i; for (i = 0; i { label1.Text = label1.Text +   + listBox1.SelectedItem.ToString(); } } } } Thanks

Abdullah Munshi · Answer

You can try this code. string s = ; foreach (ListItem li in ListBox1.Items) { if (li.Selected == true) { s = s + + li.Value; } }