Opening files

Question

Hiiii

Anyone would suggest me when i open a file and cilck ok button it should open in seperate dialog box. Here when i am clicking on open button, the dialog box appears. I selected a particular file, while opening the file its showing the path name in text box i gave to my form.

This i am using to open a file dialog, and selecting the file which is showing it into the textbox.

Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
        If OpenFileDialog1.ShowDialog() <> Windows.Forms.DialogResult.Cancel Then
            TextBox1.Text = OpenFileDialog1.FileName
        End If
    End Sub

But when i click on open buttons next to textbox, that file should open which i have selected. Here is the Image of that.

Would anyone suggest me how to write the code for that.

Regard
Mithil

Albertto Lie · Answer

hi.. maybe this help 1st u have to add some code using System.Diagnostics; then add some other code to your button event Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click If OpenFileDialog1.ShowDialog() Windows.Forms.DialogResult.Cancel Then TextBox1.Text = OpenFileDialog1.FileName Process.Start( OpenFileDialog1.FileName) End If End Sub

mithil Malhotra · Answer

Hiiii I have made Menustrip with menu File Please suggest me the code for that........ Thanks and Regard Mithil

mithil Malhotra · Answer

hiiii Albert Thanks it helped me as i go one step further doing my project work.