Popup messages

Question

Hello

I am developing a window application. I am new to c# so my problem is i want to display popup messages on my form when a new user logged into the system with valid user id and password and at that time newly logged in user should get some notification from the already logged in users.

So Please help me in this regard

Thank you

Marimuthu Arigovindasamy · Answer

Have u solved ur pbm?

Marimuthu Arigovindasamy · Answer

If you want to display the message saying Any user is already loggedin into the application then you can use the below code. //Get the current process name Process currentProcess = Process .GetCurrentProcess(); string currProcessName = currentProcess.ProcessName; // Get all the instances of current application Process [] prevAppInstance = Process .GetProcessesByName(currProcessName); if (prevAppInstance.Length > 1) { //Show error msg if the same exe is already running MessageBox .Show( The application is already runninig in this machine ); return ; } else { Application .EnableVisualStyles(); Application .SetCompatibleTextRenderingDefault( false ); Application .Run( new Form1 ()); }

Kapil Deo Malhotra · Answer

Hi Venkat As you mentioned it is Windows application (desktop) not web right? Can you explain what you mean by when new user logged in it should notify with the user already loged in. How two users will execute the Windows application from single desktop is that application is sharing some thing? Can you provide me the use case (flow) i will try to help you for sure? You can display the popup basically it will be form with no border and you can write ESC key code and it will be close down or after few seconds we can close that form. And in that form we can display the user information. But i am not sure what you mean by two different user using same application. -Kapil

Abhimanyu K Vatsa · Answer

hello.....venk why u are not using ASP.net default login create new user and user identification like controls in your project. i think it will solve ur all problems.

Crish · Answer

hi private void button1_Click( object sender System.EventArgs e) { Form dlg1 = new Form(); dlg1.ShowDialog(); } thanks Don't forget to Mark Do you like this Answer that solved your problem!