return Method

Question

This is a shabby question! :) Is there a way to use  return  method in C# to roll back to the previous used private void without calling the specific name I mean this: private void blablabla() { int a = 83959592; blobloblo(a); } private void blobloblo(int a) { if (a % 2 == 0) { roll back to blablabla() without using this method :  blablabla();  } } Sorry if it isn't clear but that's my best!

Sujeet Suman · Answer

Quang you can add 2 more textboxes on your form & take ranges from user like: long value = LongRandom( 1000000000000000000  9223372036854775807  new Random()); long m_FromRange = long.Parse(textBox1.Text); long m_ToRange = long.Parse(textBox2.Text); GenerateRandomNo( m_FromRange  m_ToRange ) ; So in this way your code length will be reduced approx 50%.

Quang Dinh Luong · Answer

Ok I'm trying now thank you! :)

Sujeet Suman · Answer

Quang by performance & visibility switch-case is far better than multiple if-else. private void beginGenerate(x) { switch (x) { case 1: break; case 2: break; } } When you call this method you can pass x like: beginGenerate(int.Parse(textBox2.Text));

Quang Dinh Luong · Answer

But what exactly does switch case different from if else? I don't even know how switch case work :( Thanks

Sujeet Suman · Answer

Quang I had gone through your code. As per code quality we should replace multiple if-else with switch case. As per my understanding I am suggesting some point please once checkout. (01.) Convert your multiple if-else with switch case (02.) Change your method definition Like: private void GenerateRandomNo( ) { long value = LongRandom( 1000000000000000000  9223372036854775807  new Random()); if(value % 2 == 0){GenerateRandomNo( )}; } Even you can manage random RANGE through loop. (03.) Store generated no in Array. Then your code will be more visible. Then you can easily put logics.

Quang Dinh Luong · Answer

I know I do right because I fixed it like i said before Before: private void checkEvenNumber(long value ) { if(value % 2 == 0) { beginGenerate(); reutrn private void valueFive() } This mean I have to create 19 private voidcheckEvenNumber for each type of value! Now: private void checkEvenNumber(long value ) { if(value % 2 == 0) { beginGenerate(); } This is hard to say! Sorry! :(

Sujeet Suman · Answer

Then Quang what is the problem? You are doing right. private void blablabla() { int a = 83959592; blobloblo(a); } private void blobloblo(int a) { if (a % 2 == 0) {  blablabla();  // This will check until odd number is not generated. } }

Quang Dinh Luong · Answer

You can see that I tried to generate different number with specific Length (User choice) And then I check if it's a even number or not if yes then re-generate if no then display that number. (Use the form2.cs I attached for better understading) It's your choice! :) Now I show this: Each of these generate a value then send it to checkEvenNumber: private void valueFive() { checkEvenNumber(value); } private void valueFour() {checkEvenNumber(value);} private void valueThree() { checkEvenNumber(value); } Then this was my problem: private void checkEvenNumber(long value ) { if(value % 2 == 0) { beginGenerate(); } Problem is that red one. (It's the fixed one) When I asked I don't know how to return mean if the  value  is even number than roll back (to which the brown code above provide the value ) to generate a different number and then check again until it's no longer a even number

Quang Dinh Luong · Answer

Sure I 'll post it sooner or later when I've done :) It takes some times!

Sujeet Suman · Answer

Quang I think you took our comments in wrong way. But our mean was not that. You are absolutely right & you can ask any thing. Ok leave these things. Quang can you share your solution here please. We are also here for learning & sharing our knowledge.

Priyaranjan K S · Answer

Cheers !

Quang Dinh Luong · Answer

It seems like I really bad at asking sorry all! By the way I fingured it out my self but thanks for helping! :)

Sujeet Suman · Answer

Quang as per my understanding and experience programming means not just achieving our goal only also taking care of meaningful coding & code quality.

Francis · Answer

I'm just curious what you want to achieve by calling like this? i'm also not sure what you exactly meaning by rollback.

Sujeet Suman · Answer

Quang as per my understanding there is no way to call as like your requirement. Yes you can do one thing that at the time of assigning value to your variable a you can put condition of calling. Like: - int a = 83959592; if(a % 2 == 0) { blablabla (); } else { blablabla ( a ); } If this is helpful for you then please accept my Answer .

Priyaranjan K S · Answer

Hi You may use the below code private void blablabla() { int a = 83959592; a=blobloblo(a); } private int blobloblo(int a) { int b=a; if(a % 2 == 0) { return a; } else { //do some calculation and modify b } return b; } You can use the return statement to stop execution of a method and return back to the calling function. Thanks Priyan If you found this useful Please mark this as Answer