Send key to JUMP TO FILE winamp window

Question

Hi I'm trying to send key stroke to winamp Jump to File window using c# when is not in foreground but I don't know how. So far I managed to send keys to winamp like c key to toggle play/pause using this example (this example work even when winamp is minimized): using System; using System.Diagnostics; using System.Runtime.InteropServices; namespace WindowsFormsApplication1 { class Test { [DllImport(User32.Dll EntryPoint = PostMessageA)] static extern bool PostMessage(IntPtr hWnd uint msg int wParam int lParam); [DllImport(user32.dll CharSet = CharSet.Auto)] public static extern IntPtr FindWindow([MarshalAs(UnmanagedType.LPTStr)] string lpClassName [MarshalAs(UnmanagedType.LPTStr)] string lpWindowName); public static void com() { IntPtr hwnd = FindWindow(Winamp v1.x null); PostMessage(hwnd 0x100 0x43 0); } } } 0x43 is the Virtual-Key Code for „C key. Can someone help me with this problem and give me an example of haw I can send keys to Jump to File window in winamp?

Vulpes · Answer

I think the problem here is that Edit is not a child of Winamp's main window but a child of some other window (apparently one with the class name #32770) down the chain. What you'll therefore need to do is to repeatedly call FindWindowEx for each level of child window until you eventually drill down to Edit.

Catalin · Answer

Hello again. Using your advice I managed to send keys to Jump to File window. Below is the script that works perfect for me: using System; using System.Diagnostics; using System.Runtime.InteropServices; namespace WindowsFormsApplication1 { class test { [DllImport(User32.Dll EntryPoint = PostMessageA)] static extern bool PostMessage(IntPtr hWnd uint msg int wParam int lParam); [DllImport(user32.dll CharSet = CharSet.Auto)] public static extern IntPtr FindWindow([MarshalAs(UnmanagedType.LPTStr)] string lpClassName [MarshalAs(UnmanagedType.LPTStr)] string lpWindowName); [DllImport(user32.dll CharSet = CharSet.Auto)] static extern IntPtr FindWindowEx(IntPtr hwndParent IntPtr hwndChildAfter string lpszClass string lpszWindow); public static void comm() { IntPtr hwnd = FindWindow(BaseWindow_RootWnd null); IntPtr chwnd1 = FindWindowEx(hwnd IntPtr.Zero BaseWindow_RootWnd null); IntPtr chwnd2 = FindWindowEx(chwnd1 IntPtr.Zero Winamp Gen null); IntPtr chwnd3 = FindWindowEx(chwnd2 IntPtr.Zero #32770 null); IntPtr chwnd4 = FindWindowEx(chwnd3 IntPtr.Zero Edit null); PostMessage(chwnd4 0x100 0x43  0); } } } 0x43 is the Virtual-Key Code for „C key. Thank you very much for your answer.

Catalin · Answer

I obtained the name of the class using Winspector. This is what I found with Winspector: - 000B099A: BaseWindow_RootWnd „Jump to file - 00090820: BaseWindow_RootWnd „Jump to file - 004E0242: Winamp Gen „Jump to file - 001707CC: #32770 „Jump to file - 00200806: Edit I changed my script into this but with no result. using System; using System.Diagnostics; using System.Runtime.InteropServices; namespace WindowsFormsApplication1 { class Test2 { [DllImport(User32.Dll EntryPoint = PostMessageA)] static extern bool PostMessage(IntPtr hWnd uint msg int wParam int lParam); [DllImport(user32.dll CharSet = CharSet.Auto)] public static extern IntPtr FindWindow([MarshalAs(UnmanagedType.LPTStr)] string lpClassName [MarshalAs(UnmanagedType.LPTStr)] string lpWindowName); [DllImport(user32.dll CharSet = CharSet.Auto)] static extern IntPtr FindWindowEx(IntPtr hwndParent IntPtr hwndChildAfter string lpszClass string lpszWindow); public static void comm() { IntPtr hwnd = FindWindow(Winamp v1.x null); IntPtr chwnd = FindWindowEx(hwnd IntPtr.Zero Edit null); PostMessage(chwnd 0x100 0x43 0); } } } Maybe these are banal questions but I'm very new in c# Thank you very much for your time.

Vulpes · Answer

Well you'll need to use FindWindowEx to get the handle for the child window and then send it the keys using PostMessage. I imagine you've obtained the window class name using Spy++. The code will be something like this: [DllImport(user32.dll CharSet = CharSet.Auto)] static extern IntPtr FindWindowEx(IntPtr hwndParent IntPtr hwndChildAfter string lpszClass string lpszWindow); // ... IntPtr chwnd = FindWindowEx(hwnd null Edit null);

Catalin · Answer

Thanks for the answer. What I want is to send keys to the window (JUMP TO FILE) not to open it. I'm trying to make an application that search a melody in winamp play list by sending keys to this window. From what I know I have to send keys to a child class of wimamp which is called Edit but I don't know how. I found some examples but it didn't work for me. I want to use PostMessage because I want to be able to sent keys even the window is not in focus. Thanks.

Vulpes · Answer

According to this link: http://blog.winamp.com/2008/08/14/keyboard-shortcuts/ the keyboard shortcut for Jump To File is 'J'. So I'd send the virtual keycode for 'J' which is 0x4A.