System.ObjectDisposedException

Question

Hi I am facing the System.ObjectDisposedException when form1 calls form2. I have created a form (form1). when I click on the button it shd call another form (form2). private void enter_Click(object sender System.EventArgs e) { frm.Show(); } This is showing the form2. But when I click again on the button its showing the following error.. Additional information: Cannot access a disposed object named Form2. Unhandled Exception: System.ObjectDisposedException: Cannot access a disposed object named Form2. Object name: Form2. Pl suggest. Cheers Rajesh

Administrator · Answer

The error is basically you are trying to access an instance of the form you have killed ! From the code you have pasted it looks like you are creating a instance of the second form outside this event function. Once you click the button the instance frm is displayed. Now when you close that window and click again it will throw this exception as the form instance(frm) you created earlier has been disposed by you closing it ! I dont know whats this application for if its ok..try creating new instance of the form each time you click the button!