The for cyclic of question

Question

hi friends Why output is 10 rather not 9. Code: #include using namespace std; void main () { const size_t array_size=10; int ia[array_size]; for (size_t ix=0;ix!=array_size;++ix) ia[ix]=ix; cout endl ; } /* my logic is:when + + X is equal to 10 you no longer perform the body of the loop statement right result cout output is 9why is output is 10. */ thanks.

Vulpes · Answer

As the variable ix is scoped to the 'for' statement and not therefore available to the cout statement I couldn't get it to compile under VC++ unless I changed it first to this: #include using namespace std; void main() { const size_t array_size=10; int ia[array_size]; size_t ix; /* now declared at function scope */ for (ix=0;ix!=array_size;++ix) ia[ix]=ix; cout } It then produced a garbage result i.e. whatever is in the next memory slot after ia[9]. That's because ix will have been incremented to 10 just before the expression : ix!=array_size fails and the for loop exits.

Ken H · Answer

hi Hemant Srivastava  i think this compile system question. thanks.

Hemant Srivastava · Answer

When loop exits at that time ix would be 10 ...right! Now the line cout endl ; will be interpreted as cout 10 ] which will be out of scope of the array (as array element would be from ia[0]... ia[9]) So accessing out of scope element ia[10] will give any random output. It may be 10 or something else..

Ken H · Answer

hi vulpes #include using namespace std; void main() { const size_t array_size=10; int ia[array_size]; size_t ix; /* now declared at function scope */ for (ix=0;ix!=array_size;++ix) ia[ix]=ix; cout } /* i think cout */

Hemant Srivastava · Answer

Output is coming 9.. I just checked the same program.

The "for" cyclic of question