XML Element

Question

Guys I'm having a little trouble formating an xml element i want to create an element like the below xml output example: (my other elements will go here as below) My problem is getting the element to output as above below is an example of an xml output of mine that is working fine i just need to add the element as above? (my above sample here) XElement xml = new XElement(Persons new XElement(Person new XElement(Server Server.Text) new XElement(User Username.Text) new XElement(Password Password.Text) new XElement(Recipient1 Recipient.Text) new XElement(Recipient2 Recipient2.Text) new XElement(Recipient3 Recipient3.Text) new XElement(Subject Subject.Text) new XElement(Message Message.Text) new XElement(Ping Ping.Text))); (and ends here) xml.Save(c:\XMLFile.xml);

Vulpes · Answer

Staying with LINQ to XML you can do this very easily with: XElement rpc = new XElement(rpc new XAttribute(module SMS) new XAttribute(method Send_SMS) new XAttribute(version 1.0)); rpc.Add(xml); // xml is your existing XElement rpc.Save(c:\XMLFile.xml);

mike Delvotti · Answer

DOH - of course thanks so much that works just fine and small snippet of code too I never imagined it could be done that quick and simple well only simple if you know how of course ;)

Vulpes · Answer

It should be XAttribute rather than XmlAttribute. Otherwise it should work fine.

mike Delvotti · Answer

Thanks guys for both the answers Vulpes I tried to code your example but get the following thrown: System.Xml.XmlAttribute' does not contain a constructor that takes '2' arguments I have no doubt that I have placed it wrong somewhere though have i done it correct as below: XElement rpc = new XElement(rpc new XmlAttribute(module SMS) new XmlAttribute(method Send_SMS) new XmlAttribute(version 1.0)); XElement xml = new XElement(Persons new XElement(Person new XElement(Server Server.Text) new XElement(User Username.Text) new XElement(Password Password.Text) new XElement(Recipient1 Recipient.Text) new XElement(Recipient2 Recipient2.Text) new XElement(Recipient3 Recipient3.Text) new XElement(Subject Subject.Text) new XElement(Message Message.Text) new XElement(Ping Ping.Text))); rpc.Add(xml); rpc.Save(c:\XMLFile.xml);

Mahesh Chand · Answer

In your requirements the rpc node has module method and version attributes. You need to use XmlAttribute class and create a node called rpc and add three attributes to the attributes collection. You can also create direct XML using XmlDocument.LoadXml as you can see below. You can also create an XmlAttribute using XmlDocument.CreateAttribute (see below). using System; using System.Xml; class test { public static void Main() { XmlDocument doc = new XmlDocument(); doc.LoadXml(  text1 text2  ); // Get the attributes of node child2 XmlAttributeCollection ac = doc.DocumentElement.ChildNodes[1].Attributes; // Print out the number of attributes and their names. Console.WriteLine( Number of Attributes:  +ac.Count ); for ( int i = 0; i . Attribute Name: ' +ac[i].Name+ ' Attribute Value: ' + ac[i].Value + ' ); // Get the 'attr1' from child1. XmlAttribute attr = doc.DocumentElement.ChildNodes[0].Attributes[0]; // Add this attribute to the attributecollection ac. ac.SetNamedItem( attr ); // 'attr1' will be removed from 'child1' and added to 'child2'. // Print out the number of attributes and their names. Console.WriteLine( Number of Attributes:  +ac.Count ); for ( int i = 0; i . Attribute Name: ' +ac[i].Name+ ' Attribute Value: ' + ac[i].Value + ' ); // Create a new attribute and add to the collection. XmlAttribute attr2 = doc.CreateAttribute( attr4 ); attr2.Value = val4 ; ac.SetNamedItem( attr2 ); // Print out the number of attributes and their names. Console.WriteLine( Number of Attributes:  +ac.Count ); for ( int i = 0; i . Attribute Name: ' +ac[i].Name+ ' Attribute Value: ' + ac[i].Value + ' ); } }