C# Math Design Logic 2

Question

I am trying to come up with a good design of the logic below

Review the example below. I am evaluating the equation below from 10.00 to 15.00 in increments .01 or 10 nano meters. 10.00, 10.01, 10.02 ........... 15.00

Find Y values from a of range 10.00 to 15.00 nano meters. I am asking how to produce the logic. There will be over two hundred values. The limit is from 10.00 to 15.00

Y = X + 3

I am trying yo pruduce the Y output limit is from 10.00 to 15.00 by 10 nanometers or.01
Example: Y is my output.

X | Y
-----------------
10.00 | 10.03
10.01 | 10.04
10.02 | 10.05
10.03 | 10.06
15.00 | 15.03

David Smith · Answer

Thanks Vuples for being so helpful.

Vulpes · Answer

That looks fine to me though I'd be careful using the double type if you need the numbers to be exact multiples of .01 as internally floating point numbers are seldom exact which can lead to cumulative round off errors. Using the decimal type avoids this though it is much slower than double and uses twice as much memory. Incidentally don't be frightened to use a simple for statement in C#. It's marginally faster than foreach and (usually) much faster than LINQ which has a lot of hidden overhead.

David Smith · Answer

Vuples I think I am going to stick with logic below I was trying to come up with another way to produce the logic below. And I am having a brain freeze if you can come up with cool way to produce the logic below that will give me the same output then i will use it. public void CalculateExpression() { double y = 0.0; Dictionary coordinatesDictionary = new Dictionary (); coordinatesDictionary.Clear(); for (double x = 3.0; x { y = x + 3; coordinatesDictionary.Add(x y); } string fn = @c:\ArrayInfo20.csv; File.AppendAllLines(fn coordinatesDictionary.Select(kvp => String.Format({0:F2} | {1:F2} kvp.Key kvp.Value))); Process.Start(fn); }

Vulpes · Answer

If you're writing the results to a file formatted to 2 dp then you need to add an extra line: Dictionary coordinatesDictionary; coordinatesDictionary = Enumerable.Range(1000 501).ToDictionary(i => i/100m i => (i + 3)/100m); File.WriteAllLines(darnell2.txt coordinatesDictionary.Select(kvp => String.Format({0:F2} | {1:F2} kvp.Key kvp.Value)));

David Smith · Answer

i try to use the logic you use the out is producing for the X values are wrong. your logic is not incrementing by 10 nano meters or .01. Your output is producing The output should produce this below instead for the equation below. Dictionary coordinatesDictionary; coordinatesDictionary = Enumerable.Range(10 15).ToDictionary(i => i/100m i => (i + 3)/100m); Wrong output X | Y ----------------- 10.01 | 10.03 10.011 | 10.04 10.012 | 10.05 10.013| 10.06 Y = X + 3 Correct Out using logic below Dictionary coordinatesDictionary = new Dictionary (); double[] arrayRangeInfo = Enumerable.Range(0 100).Select(i => (i * .01)).ToArray(); foreach (int i in Enumerable.Range(10 15)) { foreach( var itemX in arrayRangeInfo) { string xOutput = String.Format({0:F2} (i + itemX)); decimal X = Convert.ToDecimal(xOutput); decimal Y = (X + 3); coordinatesDictionary.Add(X Y); } } X | Y ----------------- 10.00 | 10.03 10.01 | 10.04 10.02 | 10.05 10.03 | 10.06

Vulpes · Answer

As LINQ has a ToDictionary() method you could condense all that into a couple of lines: Dictionary coordinatesDictionary; coordinatesDictionary = Enumerable.Range(1000 501).ToDictionary(i => i/100m i => (i + 3)/100m);

David Smith · Answer

I will check out the link but i came up with some logic it works pretty well. review below. Dictionary coordinatesDictionary = new Dictionary (); double[] arrayRangeInfo = Enumerable.Range(0 100).Select(i => (i * .01)).ToArray(); foreach (int i in Enumerable.Range(10 15)) { foreach( var itemX in arrayRangeInfo) { string xOutput = String.Format({0:F2} (i + itemX)); decimal X = Convert.ToDecimal(xOutput); decimal Y = (X + 3); coordinatesDictionary.Add(X Y); } }

Vulpes · Answer

One of the shortcomings of the Enumerable.Range method is that it can only deal with integers. To generate a range of decimals directly with a step of .01 I'd check out my article on dealing with ranges of numbers in C#: http://www.c-sharpcorner.com/uploadfile/b942f9/dealing-with-ranges-of-numbers-in-C-Sharp/

David Smith · Answer

that will not do the job when you step through the foreach below its incrementing by 1's. instead of .01 So the i below is increment by 1's instead of .01 I am basically increment by 10 nano meters. foreach (int i in Enumerable.Range(10 15)) { decimal x = i / 1000m; string xOutput = String.Format({0:F2} | {1:F2} x x + .03m); sw.WriteLine(xOutput); }

Karthik Agarwal · Answer

.03m); Change this part to .01m); in the following line string xOutput = String.Format({0:F2} | {1:F2} x x + .03m); That should do the job?

David Smith · Answer

Hi vuples Below everying is iterating through the foreach by 1's how to iterate by 10 nano meters or .01 for example below i use Enumerable.Range(10 15). I want to be able to iterate like this within the range. 10.00 10.01 10.02 10.03 10.04 10.05. 10.06 10.07 10.08 10.09 10.10 all the way to 15.00 instead 10 11 12 13 14 15 StreamWriter sw = new StreamWriter(darnell2.txt); sw.WriteLine( X | Y); sw.WriteLine(-------------); foreach (int i in Enumerable.Range(10 15)) { decimal x = i / 1000m; string xOutput = String.Format({0:F2} | {1:F2} x x + .03m); sw.WriteLine(xOutput); } sw.Close();

David Smith · Answer

Vuples you are one of the greatest to ever walk the face of the earth I had a brain freeze i think may work I trying to get out of using for loops  I use forloops in ansi C and c++ i try to think straight c sharp when i am in the c sharp environment to broaden my horizon. How would you do this in linq. I am going to test now using the Enumerable. Brb. give me 10minutes

Vulpes · Answer

To use foreach you need a sequence i.e. something that implements IEnumerable . You could do it using the LINQ method Enumerable.Range like this: using System; using System.IO; using System.Linq; class Program { static void Main() { StreamWriter sw = new StreamWriter(darnell2.txt); sw.WriteLine( X | Y); sw.WriteLine(-------------); foreach(int i in Enumerable.Range(1000 501)) { decimal x = i / 100m; sw.WriteLine(String.Format({0:F2} | {1:F2} x x + .03m)); } sw.Close(); } } You could also avoid using the temporary variable x by changing the foreach statement to: foreach(int i in Enumerable.Range(1000 501)) { sw.WriteLine(String.Format({0:F2} | {1:F2} i/100m (i + 3)/ 100m)); }

David Smith · Answer

thats was truly and error when i say y output limit. sorry. thanks you guys I actually design the logic using the for loop like you guys did above I was trying to come up with new way to simple give two limits and evaluate the Y value between the limits like you guys did above. Is there another way in c sharp to do this without using the for loop to produce this logic. Is there a way to produce this logic with a foreach or something?

Vulpes · Answer

As it takes 5 minutes to code I don't know why you're worrying about coming up with a good design. Here it is as a console app though as there are 501 pairs of numbers I've written them to a file rather than to the console: using System; using System.IO; class Program { static void Main() { StreamWriter sw = new StreamWriter(darnell2.txt); sw.WriteLine( X | Y); sw.WriteLine(-------------); for(decimal x = 10m; x { sw.WriteLine(String.Format({0:F2} | {1:F2} x x + .03m)); } sw.Close(); } }

Karthik Agarwal · Answer

using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Collections; namespace interest_calculation { class Program { static void Main(string[] args) { double X = 0.00F; double Y = 0.00F; String Dummy_x = null; //EDITED String Dummy_y = null; Console.Write(Please Enter X value : ); X = Convert.ToDouble(Console.ReadLine()); Console.WriteLine(); while (true) { Y = X + 0.03; if(Y { Dummy_x = String.Format({0:0.00} X); //EDITED Dummy_y = String.Format({0:0.00} Y); Console.WriteLine(X is :  + Dummy_x +  ||  + Y is :  + Dummy_y); //EDITED X = Y; } } } } } This is the exact code which you asked for i guess. For further assistance post a reply.

Karthik Agarwal · Answer

You said your Y value limit is 15.00 but you are still showing up 15.03 in the example you stated. You want it in the Windows form or what?