2d array with random number

Question

i had programming exam this morning...i failed...
still i wanna know how to do this.
instruction:
create 2d array [5,5] with random number from 0 to 9... and calculate the column...

        private void button1_Click(object sender, EventArgs e)
        {
            int[,] iArray = new int[5, 5];
            Random rnumber = new Random();
            int inum = rnumber.Next(0, 9);

            for (int x = 0; x < iArray.GetLength(0); x++)
            {
                for (int y = 0; y < iArray.GetLength(1); y++)
                {
                    iArray[x, y] = inum;
                    label1.Text = inum.ToString();
                }
            }
        }
my code showing only 1 random number. instead of 5 by 5 random number...

Javeed M Shaikh · Answer

Vulpes thanks for correcting the exclusive of the end-point.

Vulpes · Answer

To do it like that you'd need to adjust your code as follows (I'm assuming the label is big enough to accommodate a table): int[] iArray = new int[5 5]; Random rnumber = new Random(); int inum; string temp = ; for (int x = 0; x { for (int y = 0; y { inum = rnumber.Next(0 10); // includes 9 but excludes 10 iArray[x y] = inum; temp += inum.ToString() +  ; } if (x } label1.Text = temp; When doing something like this it's better to build the string in a temporary variable and then assign the final result to the label's Text property. This avoids the UI having to be updated on each re-assignment. It would also be more efficient to use a StringBuilder rather than a string when doing a lot of concatenations but no matter :) Finally notice that as your code stood it was only producing random numbers from 0 to 8 inclusive. When using the Next method you have to remember to make the end-point one more than you need because the random number generated is inclusive of the start-point but exclusive of the end-point.

Jonathan Crispe · Answer

the results of the is: label + (random numbers) how to put every 5 numbers in the newline. like writeline in console application.

Javeed M Shaikh · Answer

ahhhhh... change... label1.Text = inum.ToString(); to label1.Text = label1.Text +   + inum.ToString();

Jonathan Crispe · Answer

still 1 value showing up...

Javeed M Shaikh · Answer

Hi Jonathan you code is assigning it correct but the random should be calculated inside the loop otherwise it will have only one value. private void button1_Click(object sender EventArgs e) { int[] iArray = new int[5 5]; Random rnumber = new Random(); int inum; for (int x = 0; x { for (int y = 0; y { inum = rnumber.Next(0 9); iArray[x y] = inum; label1.Text = inum.ToString(); } } }