FileDialog of C#...

Question

Hello. I am working on a GUI that will write the contents of a listbox to a text file. After writing the last item, a saveFileDialog pops up. Then you can type in the name of the file and continue to save it to the desired location. My question is how can I access the name of the file I type in to save it to a variable?

Ex. I type in "testerFile" to save as the filename. How do I access that from the dialog textbox to save it to a global string?

Mahesh Chand · Answer

fileName = saveFileDialog1.FileName; http://www.c-sharpcorner.com/UploadFile/mahesh/1878/

CherRon McLemore · Answer

I found from looking at these posts that what I needed was actually the following: fileName = Path.GetFileName(save.FileName); Thanks for posting guys!!! :)

Hirendra Sisodiya · Answer

try this code: private static void saveImage() { SaveFileDialog save = new SaveFileDialog (); save.InitialDirectory = Directory.GetCurrentDirectory(); save.Filter = txt files (*.txt)|*.txt ; if (save.ShowDialog() == DialogResult .OK) { string TempfileName = save.FileName; //(whatever I typed into the SaveFileDialog box); int Index1 = TempfileName.LastIndexOf( \ ); string fileName = TempfileName.Substring(Index1+2 (TempfileName.Length - Index1)-6); } } thanks please mark as answer if it helps

CherRon McLemore · Answer

I dont think you understand what I am saying. Ex. //Global string variable string fileName; private static void saveImage() { SaveFileDialog save = new SaveFileDialog(); save.InitialDirectory = Directory.GetCurrentDirectory(); save.Filter = txt files (*.txt)|*.txt; if(save.ShowDialog() == DialogResult.OK) { fileName = (whatever I typed into the SaveFileDialog box); } } I guess my question is what is the missing code to access what I typed into the savefiledialog box?

Mahesh Chand · Answer

You just need to define either SaveFileDialog control at class level or have a string variable at class level.