How to call A partial view from _Layout.cshtml {partial view

Question

I have downloaded an application In where I have _Layout.cshtml and in this _Layout.cshtml I am calling a Partial View _Hearder the Partial view code is as below

</a>

</p>

</div>

<li>@Html.ActionLink("Services","Index","Services")</li>

<li>@Html.ActionLink("News","Index","News")</li>

<li><a href="#media" class="main">Contact Us</a></li>

</ul>

</div>

Now I want to made this _Header to get data from data base table what should i do ? i am newby MVC developer

What I have Done :

I have done a demo project in which i have created a Menu controller and i have already add entity data model which was basically my menu table then my controller is having that code

Menu Controller :

private TestEntities testEntities = new TestEntities();

public ActionResult Index()

{

ViewBag.MenuLevel1 = this.testEntities.Menus.Where(menu=>menu.ParentId==null ).ToList();

return View();

}

and I have a Folder Inside Views Folder I have Menu Folder and in Menu folder i have Index view having below code

@Model Menu.ModelTest

<!DOCTYPE html>

<html>

<head>

<title>Index</title>

</head>

<body>

<div>

<ul>

@foreach (var menuLevel1 in ViewBag.MenuLevel1)

{

<li>@menuLevel1.Name

@if (menuLevel1.Child.Count > 0)

{

<ul>

@foreach (var menuLevel2 in menuLevel1.Child)

{

<li>

@menuLevel2.Name

</li>

}

</ul>

}

</li>

}

</ul>

</div>

</body>

</html>

This runs fine i want to made this as partial view and then I want to call this partial view from _Layout , I have know how about simple Partial view but this Partial View is having Controller Action method as well so how to call This Partial view from _Layout.cshtml whatever my _Layout.cshtml is not using any Model.

Mark Tabor · Answer

it is not giving any error but showing nothing but instead if i make my Menu Partial view as static like below then it is show the static menu Home @* Services *@ @Html.ActionLink(ServicesIndexServices) @Html.ActionLink(NewsIndexMenu) @* News *@ For Sale For Rent Contact Us

Saineshwar Bageri · Answer

then it is showing or not

Mark Tabor · Answer

y Model is as below and my partial view code is i have now include IEnumerable which was not previouslly added .my partial menu code is @model IEnumerable @foreach (var menuLevel1 in ViewBag.MenuLevel1) { @menuLevel1.Name @if (menuLevel1.Child.Count > 0) { @foreach (var menuLevel2 in menuLevel1.Child) { @menuLevel2.Name } } } my

Saineshwar Bageri · Answer

Check model which you are passing to Partial view if you are using collection of model then pass collection from collection of model and if you are passing simple model then check you Partial view should take simple model as input

Mark Tabor · Answer

Thanks you for your continous response Saineshwar I have changed the Controller Name from MenuController to Menu Now i am getting that error The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BusinessApplicationTemplate.Models.Menu]' but this dictionary requires a model item of type 'BusinessApplicationTemplate.Models.Menu'.

Saineshwar Bageri · Answer

Hi Mark Tabor The Controller name must be Menu not MenuController Just make this change. @{ Html.RenderAction(DisplayMenu Menu);}

Mark Tabor · Answer

Thanks For Support Now What I did I simple Add an entity Data model into my project in models folder basically this entity data model bind the table from database {menu table} then i create a controller MenuController private PakeezaSodagranEntities3 pk = new PakeezaSodagranEntities3(); [ChildActionOnly] public ActionResult DisplayMenu() { ViewBag.MenuLevel1 = this.pk.Menus.Where(menu => menu.ParentId == null).ToList(); return PartialView(Menu pk.Menus.ToList()); } Then i add a partial view in my Shared folder with name Menu the code of the partial view is @model BusinessApplicationTemplate.Models.Menu @foreach (var menuLevel1 in ViewBag.MenuLevel1) { @menuLevel1.Name @if (menuLevel1.Child.Count > 0) { @foreach (var menuLevel2 in menuLevel1.Child) { @menuLevel2.Name } } } and then in my Layout.cshtml i am calling this partial view as @{ Html.RenderAction(DisplayMenu MenuController);} its gives an exception like that The controller for path '/' was not found or does not implement IController. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Web.HttpException: The controller for path '/' was not found or does not implement IController. Source Error: Line 31: Line 32: @* @Html.Partial(_Header)*@ Line 33: @{ Html.RenderAction(DisplayMenu MenuController);} Line 34: @RenderBody() Line 35: @Html.Partial(_Footer)

Saineshwar Bageri · Answer

Hi Mark Tabor First create a ActionMethod in Controller that will return you and Partial view. public class MenuController : Controller { [ChildActionOnly] public ActionResult DisplayMenu() { return PartialView(PartialViewName Model); } } and then call this ActionMethod on Layout as below @{ Html.RenderAction(DisplayMenu MenuController);} This will solve your Issue