how to get odd number using ArrayList

Question

how to get odd number from the above

Arraylist<int> customer = new Arraylist<int> ( 123, 12,093,45)

 

 

as

 

OUTPUT

123,093,45 

Answer 1

Hi,

 

Please try below code - 

var oddnumbers = (from m in customer.Cast<int>().ToList()
                          where m % 2 != 0
                          select m).ToList();

 

Answer 2

Hi Seshadri,

 

You can iterate throught list using for loop and divided each number with 2 to find odd or even.

 

          for(int i =0;i<customer.size();i++)
            {
                if (i % 2 != 0)
                {
                  System.out.println(i);
                }
            }

 Hope this helps

Answer 3

First ArrayList is type Independent

 

ArrayList alip= new ArrayList{123, 12, 093, 45}; 

 

foreach (var item in alip)
{
int iRet = (int)item/ 2;

if (iRet + iRet != (int)item)
{
//List the output
}
} 

Answer 4

Hi, Similar thread : https://googleweblight.com/i?u=https://stackoverflow.com/questions/13079368/how-to-output-a-list-of-numbers-in-odd-and-even-c-sharp&hl=en-IN