Jump statement

Question

Hello kind teacher. Please what does it mean when the compiler say  Unreachable code detected? I was trying to tell d program to list number 1 to 10 and write  I found 7 when it iterates to the number 7 and continues. int j; for (j = 0; j { if (j == 7) { Console.WriteLine(Found 7); continue; Console.WriteLine(j + 
); like this int j; for (j = 0; j { if (j == 7) { Console.WriteLine(Found 7); continue; it only prints 7 Thanks

Vulpes · Answer

The C# compiler will issue a warning if it detects any code which can never be executed for some reason. In your snippet. this line: Console.WriteLine(j + 
); is unreachable because it is preceded by the continue statement which will always jump over it to the end of the for statement. We can correct that and print all the numbers as follows: using System; class Program { static void Main() { int j; for (j = 1; j { if (j == 7) { Console.WriteLine(Found 7 + 
); continue; } Console.WriteLine(j + 
); } Console.ReadKey(); } } The offending line is now outside the if statement and so will print all the numbers except 7.

Tito Onowu · Answer

Thanks a million. Lots my spirit for a while!!