accept a number and print its reverse order

Question

Vulpes · Answer

For completeness here's a solution using LINQ: using System; using System.Linq; class Program { static void Main(string[] args) { Console.Write(Enter a Number : ); string number = Console.ReadLine(); Console.Write(The reverse of the number is : ); foreach(char d in number.Reverse()) Console.Write(d); Console.ReadKey(); } }

Maha · Answer

using System; class Program { static void Main() { Console.Write(Enter any number: ); string s = Console.ReadLine(); char[] arr = s.ToCharArray(); Array.Reverse(arr); Console.Write(Reverse number: ); Console.Write(arr); Console.ReadLine(); } }

Sanjeeb Lenka · Answer

hi try this: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Class1 { static void Main(string[] args) { Console.WriteLine(Enter a Number); int numb = int.Parse(Console.ReadLine()); int reverse = 0; while (numb > 0) { int rem = numb % 10; reverse = (reverse * 10) + rem; numb = numb / 10; } Console.WriteLine(Reverse number={0} reverse); Console.ReadLine(); } } }