acces textbox from another form

Question

Hello :) I have two forms and i want to acces in the main form a textbox which is placed in the second form..but the textbox isn't visible for the main form. how can i do that? thanks

Vulpes · Answer

I suspect that your form's Name property is cautaClient rather than just cauta. So I'd try changing the first line to: cauta = Application.OpenForms[ cautaClient ] as cautaClient;

Vulpes · Answer

Hmm it looks like selecting another row doesn't change the current row which is an odd state of affairs. However changing the current cell to a different row should definitely change it. So try replacing these lines: dgv.Rows[i].Selected = true; dgv.Rows[i -1].Selected = false; // make sure only a single row is selected with these: int colIndex = dgv.CurrentCell.ColumnIndex; dgv.CurrentCell = dgv.Rows[i].Cells[colIndex];

Violeta Popa · Answer

hi :) you told me earlier how to acces a control from another form and i have this code: if (cauta.Visible == true) { cauta = Application.OpenForms[cauta] as cautaClient; CheckBox cb1 = cauta.checkBox1; CheckBox cb2=cauta.checkBox2; CheckBox cb3 = cauta.checkBox3; CheckBox cb4 = cauta.checkBox4; CheckBox cb5 = cauta.checkBox5; cb1.Checked = false; cb2.Checked = false; cb3.Checked = false; cb4.Checked = false; cb5.Checked = false; } } but i keep getting this error for the bolded line and i can't understand why Object reference not set to an instance of an object.

mos martin · Answer

it worked :D ..thanks a lot :)

mos martin · Answer

hy again...i understand the changes you've made but still doesn't work properly.. for example in the datagrid i have 1 2 3 4 5 if my selected row is 3 click next and record no 4 is shown but when i click next again doesn't show 5 it's still 4.

Vulpes · Answer

The problem is that you're not changing the selected row in the DGV after each click of the picturebox and so it always starts at the originally selected row. Try this instead: private void pictureBox1_Click(object sender EventArgs e) { System.Data.SqlClient.SqlConnection conn = new System.Data.SqlClient.SqlConnection(); conn.ConnectionString = ..; conn.Open(); Acasa main = (Acasa)Application.OpenForms[Acasa]; DataGridView dgv = main.clientGridView; int i = dgv.CurrentRow.Index; int maxRows = dgv.Rows.Count; if (i != maxRows - 1) { i++; textBox1.Text = dgv.Rows[i].Cells[0].Value.ToString(); textBox2.Text = dgv.Rows[i].Cells[1].Value.ToString(); textBox3.Text = dgv.Rows[i].Cells[2].Value.ToString(); textBox4.Text = dgv.Rows[i].Cells[3].Value.ToString(); textBox5.Text = dgv.Rows[i].Cells[4].Value.ToString(); dgv.Rows[i].Selected = true; dgv.Rows[i -1].Selected = false; // make sure only a single row is selected } else { MessageBox.Show(..); } conn.Close(); // move this to the end so you always close the connection }

mos martin · Answer

another problem..i have a form which shows in some textboxes the selected row in the dgv and also i added some picturebox for the next and previous record. i don't know what's wrong..it shows the next record only at the first click then stops. Here's the code: private void pictureBox1_Click(object sender EventArgs e) { System.Data.SqlClient.SqlConnection conn = new System.Data.SqlClient.SqlConnection(); conn.ConnectionString = ..; conn.Open(); Acasa main = (Acasa)Application.OpenForms[Acasa]; DataGridView dgv = main.clientGridView; int i = dgv.CurrentRow.Index; int maxRows = dgv.Rows.Count; if (i != maxRows - 1) { i++; textBox1.Text = dgv.Rows[i].Cells[0].Value.ToString(); textBox2.Text = dgv.Rows[i].Cells[1].Value.ToString(); textBox3.Text = dgv.Rows[i].Cells[2].Value.ToString(); textBox4.Text = dgv.Rows[i].Cells[3].Value.ToString(); textBox5.Text = dgv.Rows[i].Cells[4].Value.ToString(); conn.Close(); } else { MessageBox.Show(..); } } i really appreciate your help..

Vulpes · Answer

The procedure to do this is similar to your previous thread. First you need to change the Modifiers property of the TextBox from private to internal so that it is visible to the main form. Second you need a reference to the second form. If you've opened the second form from the main form then you'll already have a reference though it needs to be saved to a private field of the form rather than a local variable. private Form2 f2; // in some method f2 = new Form2(); f2.Show(); // in some other method if (f2 != null) { TextBox tb = f2.textBox1; string text = tb.Text; // do something with text } If you haven't opened the second form from the main form then you could get a reference as you did in the previous thread: f2 = Application.OpenForms[Form2] as Form2; if (f2 != null) { // etc }