acsess specifiers

Question

how can I acsess a private member of base class in derived class? give me an example . Thank you yours chaithu

Alan · Answer

Here's a quick example of obtaining the value of a private field in the base class using reflection: using System; using System.Reflection; class Program { static void Main() { Derived d = new Derived(); Console.WriteLine(The value of parentInt is {0}d.DerivedMethod()); Console.ReadLine(); } } class Parent { private int parentInt = 3; } class Derived : Parent { public int DerivedMethod() { Type t = this.GetType().BaseType; BindingFlags bf = BindingFlags.Instance | BindingFlags.NonPublic; FieldInfo fi = t.GetField(parentInt bf); return (int)fi.GetValue(this); } } Notice that you can apply the FieldInfo.GetValue() method to the current Derived instance rather than creating a separate Parent instance. This is because the private field is still inherited by Derived even though it's not directly accessible by code within it.

Alan · Answer

You can't except by using reflection. I can give you an example of that if you can let me know what type of private member you want to access.