Application path

Question

How to get path of file(ex:test.txt) currently running in c#.

Vulpes · Answer

Well you can get the name of the currently open file by extracting it from the window title. Here's some code which does that and which allows for the possibility that multiple instances of Notepad could be open simultaneously: using System; using System.Diagnostics; class Test { static void Main() { Process[] procs = Process.GetProcessesByName(notepad); if (procs.Length > 0) { for(int i = 0; i { Console.Write(Instance {0} (Process Id = {1}) -  i + 1 procs[i].Id); string fileName = procs[i].MainWindowTitle.Replace( - Notepad ); if (fileName.StartsWith(Untitled)) { Console.WriteLine(no file open); continue; } if (!fileName.Contains(.)) fileName += .txt; Console.WriteLine(fileName); } } else { Console.WriteLine(No instance of notepad is currently running); } Console.ReadKey(); } } However to get the file path you would need to get its handle and use that to fish it out of kernel memory which would require the use of a driver. This can be done in C/C++ but would be very difficult from managed code which can only run in user mode. If you don't mind a bit of C++ then I'd check this article: http://www.codeproject.com/Articles/18975/Listing-Used-Files

brunda k · Answer

Thankyou!

Sam Hobbs · Answer

If none of the previous replies helped you then you need to clarify what you need. Since you use text.txt as an example I suspect that you are trying to ask for something different from what the other replies are suggesting.

brunda k · Answer

Thanks for the reply In the above code say i have Test.txt file running(open) then thru the above code i am getting Process notepad: C:\Windows\system32\NOTEPAD.EXE. But my requirment is to get Application Name: Test.txt Path of Application : c:/Tempfolder

Senthilkumar · Answer

Hi You can get all the files which are currently running in the operating system. If you get the file name then you can get the path. foreach (Process p in Process.GetProcesses()) { string procFile; try { procFile = p.Modules[0].FileName; } catch (Win32Exception) { procFile = n/a; } Console.WriteLine(string.Format(Process {0}: {1} p.ProcessName procFile)); } To get the current application execution path http://www.csharp-examples.net/get-application-directory/