Arithmetic Operations (32-bit floating point, 32-bit signed integer, 16-bit signed integer)

Question

Hi folks! What does "multiplying a series of number by a constant gain by using 32-bit floating point arithmetic operations (+,-,*,/)" mean? I have to multiply some numbers by 0.618 assuming the computer which will be perform the operation is restricted. The computer is capable of i)32-bit floating point arithmetic operations (+,-,*,/). ii)32-bit signed integer arithmetic operations (+,-,*,/). iii)Addition/subtraction and basic bitwise operations (aritmetic shift, inversion etc.) How can I perform such an opertion in C#? For example, how can I multiply 0.618 by -2046 by using the three capabilities mentioned independently from each other?

Ercan Kiraz · Answer

Shortly, I need to multiply two numbers in three different ways. The output is the multiplication result. But I have to write an algoritm such that a computer which is capable of performing 32-bit floating point arithmetic operations (+,-,*,/)first. In the second question I have to make the same operation by assuming the computer is only capable of 32-bit signed integer arithmetic operations (+,-,*,/)(i.e. no capability of floating point).In the last question computer can only perform + and - and basic bitwise operations. We will find a=0.618*2047,for example, but considering the limitations. I will be glad with your answers.

Kirtan Patel · Answer

Friend, Explain in Some simple way its hard to understand you what you exactly want as output? :)

Arithmetic Operations (32-bit floating point, 32-bit signed integer, 16-bit signed integer)

Nirav Vaghela