ASP

Question

I implemented Jquery Validation.Then click on submit button First it is validating after then get fired.but it is not validating ii mean ididnt enter any data....then get fired.it should not be happens . Name textbox Paasword textbox submitt but i have exception error enter @p1 scalar variable like that.. plz help me.. Thank you Pavan.

Pavan Bujji · Answer

this is ASp code: Register Here .auto-style1 { width: 131px; } .auto-style2 { width: 112px; } .auto-style3 { width: 112px; height: 30px; } .auto-style4 { width: 131px; height: 30px; } First Name: Last Name: Email: Password: Phone no:: Address I Agree Conditions jQuery(document).ready(function () { if (jQuery(#form1).validationEngine() == false) return false; }); function ShowPopup(message) { $(function () { $(#dialog1).html(message); $(#dialog1).dialog({ title: 'Message' buttons: { 'OK': function () { $(this).dialog('close'); } } modal:true draggable: false resizable: false }); }); }; this is code behind code: using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data; using System.Data.SqlClient; public partial class _Default : System.Web.UI.Page { SqlConnection con = new SqlConnection(Data Source=rana-pc\sql2008;Initial Catalog=CredentialsDB;Integrated Security=True); SqlCommand cmd; SqlDataReader rd; protected void Page_Load(object sender EventArgs e) { } protected void btnLogin_Click(object sender EventArgs e) { try { cmd = new SqlCommand(userslogin con); cmd.CommandType = CommandType.StoredProcedure; SqlParameter p1 = new SqlParameter(UserId txtEmail.Text); SqlParameter p2 = new SqlParameter(Password txtPassword.Text); cmd.Parameters.Add(p1); cmd.Parameters.Add(p2); con.Open(); rd = cmd.ExecuteReader(); if (rd.HasRows) { rd.Read(); string message = Login Successful.; ClientScript.RegisterStartupScript(this.GetType() Popup ShowPopup(' + message + '); true); } else { string message = Invalid UserName or Password.; ClientScript.RegisterStartupScript(this.GetType() Popup ShowPopup(' + message + '); true); } } catch (SqlException ex) { ClientScript.RegisterStartupScript(this.GetType() Popup ShowPopup(' + ex.Message + '); true); } finally { cmd.Dispose(); txtEmail.Text = ; txtPassword.Text = ; con.Close(); } } }

Rajeesh Menoth · Answer

Hi Share your code :)